Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
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Answer:
(x2 , y2) = (22,50)
Step-by-step explanation:
Given:
m1 : m2 = 1:4
(x1 , y1) = (7 , 5)
(X ,Y) = (10 ,14)
Find:
(x2 , y2)
Computation:
X = (m1x2 + m2x1) / (m1+m2)
10 = [(1)(x2) + (4)(7)]/(1+4)
10 = [x2 + 28]/5
22 = x2
Y = (m1y2 + m2y1) / (m1+m2)
14 = [(1)(y2) + (4)(5)]/(1+4)
14 = [y2 + 20]/5
70 = y2 + 20
50 = y2
(x2 , y2) = (22,50)
Answer:
x = -5
Step-by-step explanation:
-x = 5
*-1 *-1
-x * -1 = x
5 * -1 = -5
x = -5
Answer:
135
Step-by-step explanation:
Because the two vertical lines are parallel
that answer your question?
Answer:
A. 63 degrees
Step-by-step explanation:
Complementary angles are angles that add up to 90 degrees. You can make an equation to solve for angle N:
27 + x = 90
rearrange the equation:
90 - 27 = x
63 = x
