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klasskru [66]
3 years ago
7

Please please help me out

Mathematics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

26.6 m

Step-by-step explanation:

Given the figures are similar

linear ratio = a : b

area ratio = a² : b²

here

area ratio = 16 : 25, then

linear ratio = 4 : 5 ( square root of both area ratio parts )

let the perimeter of the larger figure be x, then by proportion

\frac{4}{21.3} = \frac{5}{x} ( cross- multiply )

4x = 106.5 ( divide both sides by 4 )

x ≈ 26.6

Hence perimeter of larger figure is approximately 26.6 m

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The midsegments the triangle have is three
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Sea f(x) = 5x + 3 entonces f(6) = ?
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Answer:

f(6)=33

Step-by-step explanation:

f(6)=5(6)+3

f(6)=30+3

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Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
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Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

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a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

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c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

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e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

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<u>Step-by-step explanation:</u>

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To find the equation of the line passing through a point and given its slope, the slope-intercept form is used to find its equation.

<u>The equation of the line when a point and slope is given :</u>

⇒ (y-y1) = m(x-x1)

where,

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Therefore, the equation of the line can be framed by,

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