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eimsori [14]
4 years ago
8

Frustration Occurs When

Physics
2 answers:
ololo11 [35]4 years ago
7 0
When a person is blocked from reaching a goal. 
pashok25 [27]4 years ago
3 0
It occurs in situation when a person is blocked from reaching there goal.
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The angle that the Sun’s rays strike a region of Earth determines the amount of heat transferred.
Lunna [17]
This statement is true. The angle that the Sun's rays strike a region of Earth determines the amount of heat transferred. For example, as you seen on TV, a laser pointing at an object and that specific angle that the rays of the laser pointed at was being melted. Same goes for the relationship between the Sun's rays and the Earth because it has the same energy that is being emitted per second. 

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4 years ago
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Which is not a medium through which a mechanical wave could travel?
Setler [38]

Mechanical Wave cannot travel in space vaccumes, which would be considered "Empty Space" in your situation.

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3 years ago
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A linebacker runs at 3 m/s and collides with a running back running towards him at 3.2
Anit [1.1K]

Answer:b

Explanation:

im in fifth grade so i guessd. gl tho heh.

3 0
3 years ago
Q) Considering the value of ideal gas constant in S.I. unit, find the volume of 35g O2 at 27°C and 72
djverab [1.8K]

Answer:

V = 0.0283 m³ = 28300 cm³

T₂ = 1200 K

Explanation:

The volume of the gas can be determined by using General Gas Equation:

PV = nRT

where,

P = Pressure of Gas = (72 cm of Hg)(1333.2239 Pa/cm of Hg) = 95992.12 Pa

V = Volume of Gas = ?

n = no. of moles = mass/molar mass = (35 g)/(32 g/mol) = 1.09 mol

R = General Gas Constant = 8.314 J/ mol.k

T = Temperature of Gas = 27°C + 273 = 300 k

Therefore,

(95992.12 Pa)(V) = (1.09 mol)(8.314 J/mol.k)(300 k)

V = 2718.678 J/95992.12 Pa

<u>V = 0.0283 m³ = 28300 cm³</u>

<u></u>

The Kinetic Energy of gas molecule is given as:

K.E = (3/2)(KT)

Also,

K.E = (1/2)(mv²)

Comparing both equations, we get:

(3/2)(KT) = (1/2)(mv²)

v² = 3KT/m

v = √(3KT/m)

where,

v = r.m.s velocity

K = Boltzamn Constant

T = Absolute Temperature

m = mass of gas molecule

At T₁ = 300 K, v = v₁

v₁ = √(3K*300/m)

v₁ = √(900 K/m)

Now, for v₂ = 2v₁ (double r.m.s velocity), T₂ = ?

v₂ = 2v₁ = √(3KT₂/m)

using value of v₁:

2√(900 K/m) = √(3KT₂/m)

4(900) = 3 T₂

<u>T₂ = 1200 K</u>

5 0
3 years ago
Two blocks are connected by a massless rope over a massless, frictionless pulley, as shown in the figure. The mass of block 2 is
Agata [3.3K]

The mass of block 1 is 1.30176 kg.

<h3>What is tension in physics?</h3>

A tension force in physics is a force developed in a rope, string, or cable when stretched under an applied force.

Tension is acted along the length of the rope/cable in a direction that is opposite to the force applied on it.

According to the question,

Mass of block 2= 11.3 kg

Kinetic friction μ=0.200

The component of the weight in the direction of the incline

W = m₂gsinθ

T = F_{f}  - W........(1)

When the force of friction

F_{f} = μ_kN

F_{f} = μ_k(m₂gcosθ)

Here , Put the value in equation 1

T = m₂gcos 31.5° - μ_km₂gcos 31.5°

We know that ,

T - m₁g = 0

T = m₁g

So,

m₁g = m₂g (Sin 31.5° - 0.200 x cos 31.5°)

m₁ = 11.3 x (0.0840 - 0.2 x 0.996)

m₁ = 11.3 x (0.1152)

m₁ = 1.30176 kg

Hence, the mass of block 1 is 1.30176 kg.

Learn more about tension here:brainly.com/question/14294135

#SPJ1

7 0
2 years ago
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