An FCC iron-carbon alloy initially containing 0.55 wt% C is exposed to an oxygen-rich and virtually carbon-free atmosphere at 13
25 K. Under these circumstances, the carbon diffuses from the alloy and reacts at the surface with the oxygen in the atmosphere -- that is, the carbon concentration at the surface position is maintained essentially at 0 wt% C. This process of carbon depletion is called decarburization. At what position will the carbon concentration be 0.20 wt% after 10 h treatment?
1 answer:
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6 and
Explanation:
The expression:
6a -
A coefficient is a numerical constant usually placed before a variable in an expression.
They are used to multiply variables.
Given equation is;
There are two variables in this expression which are;
a and - b
The coefficients in this expression are:
6 and
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Answer:
1917723.40119 m/s
Explanation:
m = Mass of deuteron =
k = Boltzmann constant =
T = Temperature =
RMS velocity is given by
The RMS velocity of the deutrons is 1917723.40119 m/s
The rms speed of the molecules of gas A is twice that of gas B. The molecular mass of A is one fourth to that of B.
Answer: Option B
<u>Explanation:</u>
Measuring the speed of particles at a given point in time results in a large distribution of values. Some molecules can move very slowly, others very fast, and because they are still moving in different directions, the speeds may be zero. (Velocity, vector quantity that corresponds to the speed and direction of the molecule.)
To correctly estimate the average velocity, you must take the squares of the mean velocity and take the square root of this value. This is known as the root mean square (rms) velocity and is shown as follows:
Where,
M – Gas’s molar mass
R – Molar mass constant
T – Temperature (in Kelvin)
Given data is rms speed for gas molecule A is twice that of gas molecule B. So,
Therefore, equating the molecule’s rms speed formula for both A and B,
On squaring both sides, we get,
By solving the above equations, we get,