An FCC iron-carbon alloy initially containing 0.55 wt% C is exposed to an oxygen-rich and virtually carbon-free atmosphere at 13
25 K. Under these circumstances, the carbon diffuses from the alloy and reacts at the surface with the oxygen in the atmosphere -- that is, the carbon concentration at the surface position is maintained essentially at 0 wt% C. This process of carbon depletion is called decarburization. At what position will the carbon concentration be 0.20 wt% after 10 h treatment?
1 answer:
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Answer: Part(a)=0.041 secs, Part(b)=0.041 secs
Explanation: Firstly we assume that only the gravitational acceleration is acting on the basket ball player i.e. there is no air friction
now we know that
a=-9.81 m/s^2 ( negative because it is pulling the player downwards)
we also know that
s=76 cm= 0.76 m ( maximum s)
using kinetic equation
where v is final velocity which is zero at max height and u is it initial
hence
now we can find time in the 15 cm ascent
using quadratic formula
t=0.0409 sec
the answer for the part b will be the same
To find the answer for the part b we can find the velocity at 15 cm height similarly using
where s=0.76-0.15
as the player has traveled the above distance to reach 15cm to the bottom
when the player reaches the bottom it has the same velocity with which it started which is 3.861
hence the time required to reach the bottom 15cm is
t=0.0409
Answer:
See the answers below.
Explanation:
We will solve this problem by calculating each part separately.
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