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Misha Larkins [42]

3 years ago

14

When 1 kg of water and 1 kg of wood absorb the same amount of heat, the change in temperature of the wood is greater than the ch

ange in temperature of the water. which property helps to explain this difference?
A. Intermolecular forces in water are greater than those in wood.
B. Intermolecular forces in water are less than those in wood.
C. The latent heat of fusion of water is less than that of wood.
D. The latent heat of fusion of water is greater than that of wood.

1 answer:

vampirchik [111]3 years ago

8 0

Your Answer Will Be C

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if a boat was moving at a velocity of 30 m/s to the south and it sailed for 30 minutes, what was the displacement of the boat?

kifflom [539]

If you move south at 30 m/s for 30 minutes, your displacement is

D = (30 mtr/s) x (30 min) x (60 sec/min)

D = (30 x 30 x 60) (mtr-min-sec/sec-min)

D = 54,000 meters south

D = <em>54 km south</em>

8 0

3 years ago

Ball A is dropped from the top of a building of height h at the same instant that ball B is thrown vertically upward from the gr

DiKsa [7]

Answer:

(2/3) times height collision occur

Explanation:

for ball A

from the kinematic equation

the distance of ball A is

$x_A = v_0 t + \frac{1}{2} at^2$

$v_0* t$ = velocity ( time ) = distance

since ball is at height, the above equation changes as

$x_A = H - \frac{1}{2} gt^2$

for ball B

$xB = v0 t - \frac{1}{2} gt^2$

the condition of collision is

xA = xB

$vA = - 2vB$ (given)

from the kinematic equation

the speed of the ball A is

$v_A = u- gt$

since initial speed of the ball A is zero

, so

$v_A = -gt$

the speed of the ball B is

$v_B = v_0 - gt$

since $v_A = - 2v_B$

$-gt = -2 ( v_0 - gt)$

$-gt = -2 v_0 +2gt$

$3gt =2 v_0$

$t = \frac{2v_0}{3g}$

since $x_A = x_B$

$H - \frac{1}{2} gt^2= v_0 t - \frac{1}{2} gt^2$

$H = v_0 t$

$= v_0 (2v_0/3g)$

$= \frac{2 v_0^2}{ 3g}$

$x_A = 2 (\frac{v_0^2}{ 3g})- \frac{1}{2} gt^2$

$= 4 \frac{v_0^2}{9g} = (2/3) H$

so, (2/3) times height collision occur

3 0

3 years ago

An electron of mass 9.11×10-31kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to t

SOVA2 [1]

Answer:

(A) Acceleration will be $240.3846\times 10^{12}m/sec^2$

(b) Time taken will be $1.4\times 10^{-8}sec$

(c) Force will be $2189.9\times 10^{-19}N$

Explanation:

We have given that electron starts from rest so initial velocity u = 0 m/sec

Final velocity $v=2.50\times 10^6m/sec$

Mass of electron $m=9.11\times 10^{-31}kg$

Distance traveled by electron $s=1.30cm =0.013m$

From third equation of motion we know that $v^2=u^2+2as$

(a) So $(2.5\times 10^6)^2=0^2+2\times a\times 0.013$

$a=240.3846\times 10^{12}m/sec^2$

(b) From first equation of motion we know that v = u+at

So $2.50\times 10^6=0+240.3846\times 10^{12}t$

$t=0.014\times 10^{-6}=1.4\times 10^{-8}sec$

(c) From newton's law we know that force

$F=ma=9.11\times 10^{-31}\times 240.3846\times 10^{12}=2189.9\times 10^{-19}N$

7 0

3 years ago

Câu hỏi: Một bộ acquy có thể cung cấp một dòng điện 2 A liên tục trong 1 giờ thì phải nạp lại. Cường độ dòng điện mà acquy này c

sleet_krkn [62]

Answer:

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6 0

3 years ago

The sound intensity at 4 m from a source is 100 W/me. What is the intensity of the sound at 12 m away from the source ?

xxTIMURxx [149]

Answer:

Intensity at 12 meters will be 11.11 W/m^2

Explanation:

Recall that the intensity of sound is inversely proportional to the square of the distance from the source. Therefore, if at 4 m the intensity is 100 W/m^2

we have: 100 W/m^2 = k/16 and therefore, k = 1600 W

Then the intensity (I) at 12 m will be:

I = k/12^2 = 1600/144 W/m^2 = 11.11 W/m^2

8 0

3 years ago