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strojnjashka [21]
3 years ago
11

What are the roots of the quadric equation y=x^2-10x+125?

Mathematics
1 answer:
olganol [36]3 years ago
8 0
5,100 um i’m not sure if that’s the answer you’re looking for
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Please hurry will give Brainliest answer please quick
Keith_Richards [23]
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2 years ago
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Find the percent decrease. Round to the nearest percent. From 96°F to 71°F​
barxatty [35]

Step-by-step explanation:

100% = 96

1% = 100%/100 = 96/100 = 0.96

the temperature changed by 96 - 71 = 25.

how many % are these 25 ?

we check how often 1% fits into 25.

that is done by division :

25 / 0.96 = 26.04166667 ≈ 26%

7 0
2 years ago
Who want to help ???
Fiesta28 [93]
For a set of trials P_{desired}=\frac{desired}{total}. In this case our desired out come is all multiples of 3: 3,6,9 and 12. The total number of outcomes can be found as 100 by adding up all the frequencies. Thus our experimental probability is P_{x=3n}=\frac{6+14+12+1}{100}=\frac{33}{100}=33\%.
8 0
3 years ago
The nurse develops a plan to prevent atelectasis in a postsurgical client. which intervention will be effective?
zloy xaker [14]
<span>Deep breathing every hour while supervised would be an effective intervention that a nurse might plan. This would help to prevent atelectasis in a post-surgical patient. Atelectasis is the complete or partial collapse of a lung. This is a very common complication following many procedures.</span>
5 0
3 years ago
What is -5/4 divide 4/3=?
atroni [7]

Answer:

-\frac{15}{16}

Step-by-step explanation:

-\frac{5}{4} ÷ \frac{4}{3}

Divide -\frac{5}{4} by \frac{4}{3} by multiplying -\frac{5}{4} by the reciprocal of \frac{4}{3}.

-\frac{5}{4} × (\frac{3}{4} )

Multiply -\frac{5}{4} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

\frac{-5 x 3}{4x4}

Do the multiplications in the fraction \frac{-5 x 3}{4x4}

\frac{-15}{16}

Fraction \frac{-15}{16} can be rewritten as -\frac{15}{16} by extracting the negative sign.

-\frac{15}{16}

Hope it helps and have a great day! =D

8 0
2 years ago
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