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Blababa [14]
3 years ago
14

A rectangular area has dimensions 432 feet by 345 feet. Using front-end estimation on the dimensions, what is an estimate of the

amount of fencing required to enclose the rectangular area? A. 1200 ft. B. 1300 ft. C. 1400 ft. D. 1600 ft.
Mathematics
1 answer:
madam [21]3 years ago
4 0

Answer:

Option C. 1400 ft

Step-by-step explanation:

we know that

In a <u><em>Front End Estimation</em></u> we keep only one number in the front and all the others became zeros

The perimeter of a rectangular area is equal to

P=2(L+W)

where

L is the length and W is the width

we have

L=432\ ft\\W=345\ ft

Applying front-end estimation

we have

432\ ft=400\ ft\\345\ ft=300\ ft

Find the perimeter

P=2(400+300)

P=1,400\ ft

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Zack watered his garden with 1 3/8
victus00 [196]

Answer:

<u>The correct answer is that Zack used 2 7/8 gallons to water his garden on the fifth week.</u>

Step-by-step explanation:

Let's find out the pattern Zack is using to water his garden, this way:

First week =  1 3/8  gallons of water

Second week = 1 3/4 gallons of water = 1 3/8 + 3/8 = 1 6/8 = 1 3/4

Third week = 2 1/8 gallons of water = 1 3/4 + 3/8 = 1 6/8 + 3/8 = 2 1/8

The constant of adding every week is 3/8 gallons, therefore,

Fourth week = 2 1/8 + 3/8 = 2 4/8 = 2 1/2 gallons of water

Fifth week = 2 1/2 + 3/8 = 2 4/8 + 3/8 = 2 7/8 gallons of water

<u>The correct answer is that Zack used 2 7/8 gallons to water his garden on the fifth week.</u>

3 0
3 years ago
A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of
krek1111 [17]

Answer:

Step-by-step explanation:

it is given that Square contains a chord of of the circle equal to the radius thus from diagram

QR=chord =radius =R

If Chord is equal to radius then triangle PQR is an equilateral Triangle

Thus QO=\frac{R}{2}=RO

In triangle PQO applying Pythagoras theorem

(PQ)^2=(PO)^2+(QO)^2

PO=\sqrt{(PQ)^2-(QO)^2}

PO=\sqrt{R^2-\frac{R^2}{4}}

PO=\frac{\sqrt{3}}{2}R

Thus length of Side of square =2PO=\sqrt{3}R

Area of square=(\sqrt{3}R)^2=3R^2

Area of Circle=\pi R^2

Ratio of square to the circle=\frac{3R^2}{\pi R^2}=\frac{3}{\pi }

5 0
3 years ago
Find the area of the kite
Elis [28]
d_1=9.2m+9.2m=18.4m\\d_2=6.9m+13.8m=20.7m\\\\Area\ of\ the\ kite:A=\frac{d_1\times d_2}{2}\\\\A=\frac{18.4\times20.7}{2}=9.2\times20.7=190.44\ (m^2)
6 0
3 years ago
Read 2 more answers
Please answer !!!!!!!! Will mark brainliest whoever answers correctly !!!!!!!!
kirill115 [55]

Answer:

g(q) = 5/8q

Step-by-step explanation:

-7q + 12r = 3q - 4r

Add 4r to each side

-7q + 12r+4r  = 3q - 4r+4r

-7q +16r = 3q

Add 7q to each side

-7q+7q +16r = 3q+7q

16r = 10q

Divide each side by 16

16r/16 = 10q/16

r = 5q/8

g(q) = 5/8q

5 0
3 years ago
Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5
Fynjy0 [20]

Answer:

a(6) = 37.97

Step-by-step explanation:

If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is

a(n) = 5*r^(n - 1).

Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97

5 0
2 years ago
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