Ok
First factor out the first 2 terms as follows:-
y = 1/2(x^2 - 8x) + 21
Now complete the square on x^2 - 8x:-
y = 1/2[ (x - 4)^2 - 16] + 21
y = 1/2(x - 4)^2 - 8 + 21
y = 1/2(x - 4)^2 + 13 Answer
Answer:
B) >
Step-by-step explanation:
You can compare fractions by converting them into a decimal and examining which one has the greater value.
3/4 = 0.75
3/5 = 0.6
From this, we can see that 3/4 is greater than 3/5, so the sign will be >.
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note: You can also find the least common denomiator between the fractions and compare their numerator values to find which one is bigger. The one with the larger numerator will be the greater fraction.
hope this helps!
You subtract 4/9x frm 8/9x which is 4/9x = 8 then you multiply 9 to 8 so it is 4x = 72. After that, you divide 4 from 72 and get 18
Sum f(k)=4k-10 for k=1 to 18.
We sum each term separately and add the sums.
![\sum_1^{18}4k=4\sum_1^{18}k=4[18(1+18)/2]=4*9*19=684](https://tex.z-dn.net/?f=%5Csum_1%5E%7B18%7D4k%3D4%5Csum_1%5E%7B18%7Dk%3D4%5B18%281%2B18%29%2F2%5D%3D4%2A9%2A19%3D684)

Therefore the required sum is 684-180=504