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3 years ago

The less dense areas in a sound wave are called _____.

Chemistry

2 answers:

Rasek [7]3 years ago

4 0

Answer:

rarefaction is the correct answer.

Explanation:

Rarefaction is defined as the reduction in the density item.

Rarefaction takes place mostly when the particles present in the gas become extra scattered out.

Sound need to a medium to travel and the air is the most common medium. As the vibrating object move in the forward direction, the air gets compressed and creates a region of high pressure and the high-pressure area is called compression. This compression begins to move apart from the vibrating object.When the vibrating object moves in the backward direction, it creates less dense areas called rarefaction.

Thus The less dense areas in a sound wave are called rarefaction.

Vitek1552 [10]3 years ago

3 0

The less dense areas in a sound wave is called a rarefaction or rarefactions if there are multiple.

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For ethanol, propanol, and n-butanol the boiling points, surface tensions, and viscosities all increase. What is the reason for

vekshin1

Answer:

First choice. The boiling points, surface tension, and viscosities all increase because the strength of dispersion forces increases.

Explanation:

Those properties, boiling points, surface tension, and viscosities are due to the attractive intermolecular forces of the substances.

Ethanol, propanol, and n-butanol (three alcohols) have these chemical formulae:

Ethatnol: CH₃CH₂ OH
Propanol: CH₃ CH₂ CH₂ OH
n-butanol: CH₃CH₂ CH₂ CH₂ OH

So, the molecules of those substances are polar and exhibit all these types of intermolecular bonding forces:

Dipole-dipole interactions: attractive forces between the positive end of one polar molecule and the negative end of another polar molecule;

London dispersion forces: a temporary attractive force that results of temporary assymetry in the electron distribution around the nuclei. This occurs when the electrons in two adjacent atoms occupy positions that cause the atoms form temporary dipoles. These forces exist between any two molecules when they are very, very close to each other (almost touching).

Hydrogen bonding: the strongest intermolecular force. It is a type of dipole-dipole attraction, which arises between an hydrogen atom covalently bonded to a very electronegative atom (in this case oxygen) and the very electronegative atom (oxygen) of a neighboor molecule.

What answer your question is that such hydrogen bonding and dipole-dipole interactions are similar for all the three alcohols, ethanol, propanol, and n-butanol, so they are not responsible for the difference in the mentioned properties, boiling points, surface tension, and viscosities. What is different is the dispersion forces: they increase as the size of the alcohols increase.

As the molecules contain more carbon atoms, lengthen, contain more electrons and, as consequence, the dispersion forces become greater (the magnitude of the temporary dipoles formed increase). This explains the validity of the first statement, that the boiling points, surface tension, and viscosities, all increase because the strength fo the dispersion forces increase.

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Andru [333]

Answer: Please see below for answers

Explanation: Matching appropriate labels , we have

1)3/4 of the way to second equivalence point of a diprotic acid/strong base titration-- pH=pka₂

equivalence point of a weak base/strong acid titration=pH<7

equivalence point of a strong acid/strong base titration= pH=7

equivalence point of a weak acid/strong base titration=pH>7

half-way to equivalence point of a weak acid/strong base titration pH =pka

where

pH gives the measure of the amount of concentration of hydrogen ions in an aqueous solution.

pKa is known as acid dissociation constant which explains the equilibrum at which a chemical species can give out or receive proton

pka₂ is the acid dissociation constant for the second ionization energy.

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sdas [7]

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3 years ago

Please help

Colt1911 [192]

A i belive is the correct answer

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3 years ago