Answer:
C3H6 + 9/2 O2 ⇒ 3CO2 + 3 H2
according to the equation, mole of O2 =9/2 * mole of C3H6
so the liters of O2 gas = 9/2 * C3H6 gas = 9/2 * 0.61 =2.745l
similarly, according to the equation, CO2 gas = 3 * C3H6 gas=3*0.61=1.83l
Explanation:
The answer is 2.2 g.
First, we need to calculate a molar mass (M) of AgNO₃<span>. The molar mass is a mass of 1 mole of a substance. It is the sum of relative atomic masses (Ar), which are masses of atoms of the elements.
Relative atomic mass of Ag: Ar(Ag) = 108 g
Relative atomic mass of N: Ar(N) = 14 g
Relative atomic mass of O: Ar(O) = 16 g
So, the molar mass of </span>AgNO₃ is:
M(AgNO₃) = Ar(Ag) + Ar(N) + 3Ar(O) = 108 + 14 + 3*16 = 170 g
Now, we can make a proportion:
If 108 g of Ag is in 170 g of AgNO₃, how many silver will be in 3.4 g of AgNO₃:
108 : 170 = x : 3.4
After crossing the products:
x = 108 × 3.4 ÷ 170 = 2.16 g ≈ 2.2 g
The azide ion N3- can actually be represented by 3
resonance structures.
(check attached image for the structures)
<span>Among the three, the Structure 1 is the most important
one. While structure 3 almost makes no contribution due to the positive charges
located on the adjacent atoms and the overall higher formal charge.</span>
