5/1 = 10/x
5x = 10
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5. 5
X = 2 dollars
Explanation:
As we know that density is the amount of mass present in a liter of solution.
Mathematically, density =
As it is given that density of water is 1 g/ml and volume is 175 mL. So, mass of water will be calculated as follows.
density =
1 g/ml =
mass = 175 g
It is known that 18 g of water contains 1 mole of water. Hence, number of moles present in 175 g of water will be calculated as follows.
No. of moles =
=
= 9.72 mol
This means that we have 9.72 moles of ethanol also.
Hence, volume of ethanol present in 175 ml of water will be as follows.
No. of moles of ethanol =
9.72 mol =
Volume = 566.69 ml
Thus, we can conclude that 566.69 ml volume of ethanol contains the same number of molecules as are present in 175 ml of .
Answer:
First one: group
Second one: period
Third one: number of valence electrons
Last one: increases
CO+2 H2=CH3OH
2.85 mol Co x (2mol H2/1 mol Co)=5.70 mol just concert to grams
5.70 mol H2 x (2 g H2/1 mol H2) =11.40 grams of H2
Answer:
Electron-pair geometry: tetrahedral
Molecular geometry: trigonal pyramidal
Hybridization: sp³
sp³ - 4 p
Explanation:
There is some info missing. I think this is the original question.
<em>For NBr₃, What are its electron-pair and molecular geometries? What is the hybridization of the nitrogen atom? What orbitals on N and Br overlap to form bonds between these elements?</em>
<em>The N-Br bonds are formed by the overlap of the ___ hybrid orbitals on nitrogen with ___ orbitals on Br.</em>
<em />
Nitrogen is a central atom surrounded by 4 electron domains. According to VESPR, the corresponding electron-pair geometry is tetrahedral.
Of these 4 electron domains, 3 represent covalent bonds with Br and 1 lone pair. According to VESPR, the corresponding molecular geometry is trigonal pyramidal.
In the nitrogen atom, 1 s orbital and 3 p orbitals hybridize to form 4 sp³ orbitals for each of the electron domains.
The N-Br bonds are formed by the overlap of the sp³ hybrid orbitals on nitrogen with 4p orbitals on Br.