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AysviL [449]
3 years ago
6

Someone help please

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer: (x+-0.5)²=0

Step-by-step explanation:

4x²-4x+1=0

(2x-1)²=0 ⇔ completing the square

--------------------------------------------

since the question asked for the x should be 1, then we should divide 2x by 2 so to get rid of the 2 in front of the x.

this will change the original equation into: (x+(-0.5))²=0

------------------------------------------------------------------------------------------------------------

You can also directly divide 4 from 4x²-4x+1=0 to get rid off the terms in front of x.

x²-x+0.25=0

(x-0.5)²=0

(x+(-0.5))²=0

alina1380 [7]3 years ago
7 0

Step-by-step explanation:

Hey, there!

Here,

= 4 {x}^{2}  - 4x + 1

or ,\: ( {2x)}^{2}  - 2.2x .1 + 1

or ,\: ( {2x - 1)}^{2}

We got this because,

( {2x - y)}^{2}  = 4 {x}^{2}  - 4x + 1

By using formula,

( {x - y)}^{2}  =  {x}^{2}  - 2xy + 1

<em>Hope it helps</em><em>.</em><em>.</em>

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