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Zinaida [17]
3 years ago
13

Which expression converts 100 inches per minute to feet per minute?

Mathematics
1 answer:
Rudik [331]3 years ago
3 0
Speed and velocity is the answer
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What is the purpose of calculating a confidence interval? Multiple Choice To provide a range of values that has a certain large
Nadusha1986 [10]

Answer:

To provide a range of values that, with a certain measure of confidence, contains the population parameter of interest.  

To provide a range of values that has a certain large probability of containing the population parameter of interest.

Step-by-step explanation:

For estimating a parameter value, it is important to know the statement or degree of confidence that the interval contains the parameter value along with knowing the point estimate and the amount of possible error in the point estimate (which is the interval likely to contain the parameter value).Thus , an interval estimate of a population parameter is the confidence interval with a statement of confidence that the interval contains the parameter value. The confidence interval is a range of values around the statistic that are believed to contain, with a certain probability (say 99%) the true value of that statistic or the population value.

8 0
4 years ago
Solve for y in 7y - 3/4 = -1/4y - 1/3
iris [78.8K]
Answer for y is y=5/87
4 0
3 years ago
If 15/3 greater than 7, then 15/7 is less than 3 true or false
Ludmilka [50]

Answer:

True

Step-by-step explanation:

15/7 is about 2.14 which is less than 3

3 0
3 years ago
Find the midpoint of MN. M(-3,8) and N(-7-6)
ohaa [14]

Step-by-step explanation:

use the midpoint formula

-3+-7/2, 8+-6/2

(-5, 1)

3 0
3 years ago
An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer
liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1

So probabaility for \mathrm{X}=1 is

P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679

So expected frequency for X=1 is 0.3679^{*} 30=11.037 (or \left.11.04\right) .

8 0
3 years ago
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