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SVEN [57.7K]
4 years ago
6

B. How do the stars' radii compare with their mass? 1

Chemistry
1 answer:
trasher [3.6K]4 years ago
5 0

Answer: The bigger the radius the more the mass.

Explanation:

You might be interested in
An naoh solution contains 1.90 mol of naoh, and its concentration is 0.555 m. what is its volume?
Firlakuza [10]
0.555 = 1.90/V
⇒ V = 1.90/0.555
⇒ V = 3.423 liter
6 0
3 years ago
A 0.43g samle of KHP required 24.11cm of NaOH for neutralization. Calculate the molarity of NaOH
expeople1 [14]

Answer:

0.083 M

Explanation:

We'll begin by calculating the number of mole in 0.43 g of KHP (potassium hydrogen phthalate, C₈H₅O₄K). This is can be obtained as follow:

Mass of C₈H₅O₄K = 0.43 g

Molar mass of C₈H₅O₄K = (8×12) + (5×1) + (16× 4) + 39

= 96 + 5 + 64 + 39 = 204 g/mol

Mole of C₈H₅O₄K =?

Mole = mass / molar mass

Mole of C₈H₅O₄K = 0.43 / 204

Mole of C₈H₅O₄K = 0.002 mole

Next, we shall determine the number of mole of NaOH required to react with 0.43 g (i.e 0.002 mole) of KHP. This can be obtained as follow:

C₈H₅O₄K + NaOH → C₈H₄O₄KNa + H₂O

From the balanced equation above,

1 mole of KHP reacted with 1 mole of NaOH.

Therefore, 0.002 mole of KHP will also react with 0.002 mole of NaOH.

Next, we shall convert 24.11 cm³ to L. This can be obtained as follow:

1000 cm³ = 1 L

Therefore,

24.11 cm³ = 24.11 cm³ × 1 L / 1000 cm³

24.11 cm³ = 0.02411 L

Finally, we shall determine the molarity of NaOH. This can be obtained as follow:

Mole of NaOH = 0.00 2 mole

Volume = 0.02411 L

Molarity of NaOH =?

Molarity = mole /Volume

Molarity of NaOH = 0.002 / 0.02411

Molarity of NaOH = 0.083 M

3 0
3 years ago
Which of the following is improper isotope notation? Explanation: Nineteen is potassium's atomic number
sasho [114]

Answer:

C. Potassium-19 .

Explanation:

Hello!

In this case, since isotopes are known be atoms of the same element with equal atomic number but different mass number, we can consider the case of carbon which has two natural occurring ones, carbon-12 and carbon-13 whereas carbon-12 has the greatest abundance. However, isotope notation may take two forms:

1. Symbol of the element followed by a dash indicating the mass number of the isotope, for instance: C-12, K-39, and so on.

2. Name of the element followed by a dash indicating the mass number of the isotope, for instance: Carbon-12, Potassium-39, and so on.

In such a way, the improper isotope notation is C. Potassium-19 , considering that A should be K-39 because atomic symbol of potassium is K, not k.

Best regards!

7 0
3 years ago
PLS I REALLY NEED HELP DUE FODAY
Gekata [30.6K]

<u>Answer:</u> The equilibrium constant for the reaction is 54.47

<u>Explanation:</u>

The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term K_{eq}

The given chemical equation follows:

H_2+I_2\rightleftharpoons 2HI

The expression for equilibrium constant will be:

K_{eq}=\frac{[HI]^2}{[H_2][I_2]}

We are given:

[HI]_{eq}=1.3544\times 10^{-2}M

[H_2]_{eq}=4.5647\times 10^{-3}M

[I_2]_{eq}=7.378\times 10^{-4}M

Putting values in above expression, we get:

K_{eq}=\frac{(1.3544\times 10^{-2})^2}{(4.5647\times 10^{-3})(7.378\times 10^{-4})}\\\\K_{eq}=54.47

Hence, the equilibrium constant for the reaction is 54.47

3 0
3 years ago
Can anyone help. I don't understand
maksim [4K]
Brooo we have the same name
7 0
3 years ago
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