Answer:
Explanation:
idk why all u guys like trump who do.. hes just a big pain in the a*s.
Molarity is defined as the number of moles of solute in 1 L of solution
number of moles of NaI - 10.7 g / 150 g/mol = 0.0713 mol
there are 0.0713 mol in 0.250 L
we need to find the number of NaI moles in 1 L
if 0.250 L contains - 0.0713 mol
then 1 L contains - 0.0713 mol / 0.250 L = 0.285 mol/L
molarity is 0.285 M
Sorry I accidentally touched it
Answer:
[Ba^2+] = 0.160 M
Explanation:
First, let's calculate the moles of each reactant with the following expression:
n = M * V
moles of K2CO3 = 0.02 x 0.200 = 0.004 moles
moles of Ba(NO3)2 = 0.03 x 0.400 = 0.012 moles
Now, let's write the equation that it's taking place. If it's neccesary, we will balance that.
Ba(NO3)2 + K2CO3 --> BaCO3 + 2KNO3
As you can see, 0.04 moles of K2CO3 will react with only 0.004 moles of Ba(NO3) because is the limiting reactant. Therefore, you'll have a remanent of
0.012 - 0.004 = 0.008 moles of Ba(NO3)2
These moles are in total volume of 50 mL (30 + 20 = 50)
So finally, the concentration of Ba in solution will be:
[Ba] = 0.008 / 0.050 = 0.160 M
Total weight = 1 + 35.45 + 3 * 16 = 84.45
H = 1 / 84.45 * 100% = 1.18%
Cl = 35.45 / 84.45 * 100% = 41.98%
O = 48 / 84.45 * 100% = 56.84%