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inessss [21]
3 years ago
13

I’m not sure how to do this, please help. It’s a mole to mole stoich worksheet.

Chemistry
1 answer:
wlad13 [49]3 years ago
3 0

Answer: 4.05 mol O2, 15.36 mol H2O

Explanation:

I can answer each question individually if you post them individually.

2a. 3.24 mol NH3 * (5 mol O2 / 4 mol NH3) = 4.05 mol O2

2b. 12.8 mol O2 ( 6mol H2O/ 5 mol O2) = 15.36 mol H2O

Essentially what I did was dimensional analysis. Multiplying in a way that the units cancel out so the only thing remains is what each question asks for.

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In most lewis dot structures of neutral compounds, carbon as the central atom will be bound to a maximum of how many atoms, nitr
Fittoniya [83]
The total number of elements that one particular element can bond to can be determined by simply drawing the Lewis structure of the element.

Place the chemical symbol
Then look at the group number = valence electrons
Distribute the valence electrons around the atom.

C = 4 bonds
N = 3 bonds
O = 2 bonds
7 0
3 years ago
A sample of ammonia gas at 75°c and 445 mm hg has a volume of 16.0 l. what volume will it occupy if the pressure rises to 1225 m
ioda
In this kind of exercises, you should  use the "ideal gas" rules: PV = nRT
P should be in Pascal: 
445mmHg = 59328Pa
1225mmHg = 163319Pa

V should be in cubic meter:
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R = \frac{PV}{nT} = constant
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V2 = \frac{P1 V1}{P2} = \frac{445 0.016}{1225}
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7 0
3 years ago
What's the deffinition of igneous rock
Aliun [14]
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</span>



7 0
3 years ago
Read 2 more answers
I need help with my science vocabulary!!! Please help!
AVprozaik [17]

Answer:

1. B

2. E

3. A

4. D

5. C

~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hope I helped!!!

GL :)

5 0
3 years ago
Unknown # 41
sveta [45]

Answer:

KI

Explanation:

From the question, we can see that a qualitative analysis of the compound shows that it has a lilac flame colour. The lilac flame colour corresponds to the potassium ion (K^+).

Again, the test of addition of HNO3(aq) and AgNO3(aq) to a solution is a test for halogens. If the result is a green precipitate, then the ion present is the iodide ion (I^-).

Hence, the compound must be KI.

4 0
2 years ago
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