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Firdavs [7]
3 years ago
9

Please help! I'm confused on a few of these, 100 points!

Chemistry
2 answers:
Aliun [14]3 years ago
3 0
I cannot see the picture
Kryger [21]3 years ago
3 0
Reupload ^^ there’s no picture
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3 years ago
N2(g) + 3H2(g) => 2NH3(g) Write the reaction again as a balanced reaction
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3 years ago
What is the minimum volume of 5.50 M HCl necessary to neutralize completely the hydroxide in 718.0 mL of 0.183 M NaOH
Deffense [45]

The volume of HCl required is 23.89 mL

Calculation of volume:

The reaction:

HCl + NaOH \rightarrow NaCl + H_2O

As HCl and NaOH react in 1 : 1 ratio.

Volume of NaOH= 718 mL

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Volume of HCl= ?

Concentration= 5.50M

Using the dilution formula:

M_1\times V_1(NaOH)= M_2\times V_2(HCl)

0.183\times 718= 5.50 \times V_2\\V_2=\frac{131.394}{5.50} \\V_2 = 23.89 \,mL

Therefore,

Volume of HCl required will be 23.89 mL.

Learn more about neutralization reaction here,

brainly.com/question/1822651

#SPJ4

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2 years ago
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