Question

....need help on this ​

Answer 1

Answer:

ASA statement

Step-by-step explanation:

In quadrilateral ABCD, diagonal AC bisects $\angle BAD$ and $\angle BCD$ (given)

Next

$In\: \triangle ABC \: and \: \triangle ADC$

$\angle CAB\cong\angle CAD$

(By angle bisector property)

$AC\cong AC.... (common\: side)$

$\angle ACB\cong\angle ACD$

(By angle bisector property)

$\therefore \triangle ABC \cong \triangle ADC$

(By ASA Statement)