B is the answer your welcome
V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
To determine the solution of the quadratic equation, use the quadratic formula which states that,
x = ((-b +/- sqrt (b² - 4ac)) / 2a
From the equation, a = 1, b = 14, and c = 112. Substituting these to the quadratic formula,
x = <span>((-14 +/- sqrt (14² - 4(1)(12)) / 2(1) = indeterminate
Thus, the equation does not a real number solution. </span>
Any number over its self. for example 1,999/1,999
Answer:
B
Step-by-step explanation:
First, we are decreasing the number so it has to be a decrease.
Next, we divide 7/31 and get around 0.23, which also represents 23 percent.
This only shows that 7 is 23 percent of 31, so we need to find the decrease by seeing the difference of 100 and 23.
We get 100 - 23 = 77, and because it is a decrease we get B.
