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Nataliya [291]
3 years ago
15

Which statement best describes the process of making a solution by diluting a stock solution?

Chemistry
1 answer:
Alchen [17]3 years ago
8 0
A concentrated solution
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In the process of eating, what kind of energy in food is transformed into heat energy by your body?
Rama09 [41]

Answer:The chemical energy

Explanation:because The chemical energy in the food you eat is changed into another kind of chemical energy that your body can use. Your body then uses that energy to give you the kinetic energy that you use in everything you do.

4 0
3 years ago
Read 2 more answers
A sample of P2Cl5 contains 179 g of phosphorous, how many grams of chlorine are present? Please show step by step thx!
natima [27]

Answer:

About 512 g.

Explanation:

We are given a sample of P₂Cl₅ that contains 179 grams of phosphorus, and we want to determine the grams of chlroine that is present.

Thus, we can convert from grams of phosphorus to moles of phosphorus, moles of phosphorus to moles of chlorine, and moles of chlorine to grams of chlorine.

From the formula, there are two moles of P for every five moles of Cl. The molecular weights of P and Cl are 30.97 g/mol and 35.45 g/mol, respectively. Hence:

\displaystyle 179\text{ g P} \cdot \frac{1\text{ mol P}}{30.97\text{ g P}} \cdot \frac{5\text{ mol Cl}}{2\text{ mol P}} \cdot \frac{35.45\text{ g Cl}}{1\text{ mol Cl}} = 512\text{ g Cl}

In conclusion, there is about 512 grams of chlorine present in the sample.

Alternatively, we can mass percentages. The mass percent of phosphorus in P₂Cl₅ is:


\displaystyle \% \text{P} = \frac{2(30.97)}{5(35.45) + 2(30.97)} = 25.90\%

Because there are 179 grams of phosphorus, the total amount of sample present is:


\displaystyle \begin{aligned} 25.90\% \cdot  m_T  & = 179\text{ g P} \\ \\ m_T & = 691.1 \text{ g}\end{aligned}

Therefore, the amount of chlorine present is 691.1 g - 179 g, or about 512 g, in agreement with our above answer.

8 0
3 years ago
What is the empirical formula of ascorbic acid, given that the pseudoformula is C3.407 H4.53 O3.406??
Tom [10]
To determine the empirical formula of ascorbic acid, we divide the lowest fraction with the other values. For this case, we divide everything with 3.406. We do as follows:

C = 3.407 / 3.406 = 1
H = 4.53 / 3.406 = 1.33
O = 3.406 / 3.406 = 1

So, you have CHO

Hope this answers the question. Have a nice day.
4 0
4 years ago
Read 2 more answers
what temperature does water freeze using degrees Celsius and what is the basic unit for measuring mass
Olin [163]

Freezing point is the temperature at which a substance undergoes a phase transition from liquid to solid state. Water converts from liquid state to solid ice at a temperature of 0^{0}C.

Mass is the amount of matter contained in a substance. The SI unit of mass is kilogram. 1 kilogram is equal to 1000 g. One kilogram is defined as the mass of one cubic decimeter of water at the freezing point of water.

5 0
4 years ago
A 8.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
Ne4ueva [31]

Answer:

C3H6.

Explanation:

Data obtained from the question:

Mass of the compound = 8g

Mass of CO2 = 24.01g

Mass of H2O = 13.10g

Next, we shall determine the mass of C, H and O present in the compound. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of C in compound = Mass of C/Molar Mass of CO2 x 24.01

=> 12/44 x 24.01 = 6.5g

Mass of H in the compound = Mass of H/Molar Mass of H2O x 13.1

=> 2x1/18 x 13.1 = 1.5g

Mass of O in the compound = Mass of compound – (mass of C + Mass of H)

=> 8 – (6.5 + 1.5) = 0

Next, we shall determine the empirical formula of the compound. This is illustrated below:

C = 6.5g

H = 1.

Divide by their molar mass

C = 6.5/12 = 0.54

H = 1.4/1 = 1.

Divide by the smallest

C = 0.54/0.54 = 1

H = 1/0.54 = 2

Therefore, the empirical formula is CH2

Finally, we shall determine the molecular formula as follow:

The molecular formula of a compound is a multiple of the empirical formula.

Molecular formula = [CH2]n

[CH2]n = 44

[12 + (2x1)]n = 44

14n = 44

Divide both side by 14

n = 44/14

n = 3

Molecular formula = [CH2]n = [CH2]3 = C3H6

Therefore, the molecular formula of the compound is C3H6

4 0
3 years ago
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