Answer:
What is the empirical formula of the compound?
Explanation:
When the relative masses of elements in a hydrocarbon are given, it is possible to use this information to obtain the empirical formula by dividing the given masses of each element by the relative atomic masses of the element. The lowest ratio is now used to divide through to obtain the empirical formula of the compound.
The empirical formula only shows that ratio of atoms of each element present in the compound. From the information provided, the empirical formula of the compound is CH2. Hence the answer.
The nucleus of an atom contain neutrons and protons, and energy levels surround the nucleus, in rings and contain electrons
Answer:
17.5 g/cm³
Explanation:
We can solve this particular problem by keeping in mind the <em>definition of density</em>:
As the problem gives us both <em>the mass and the volume</em> of the box, we can now proceed to <u>calculate the density</u>:
The density of the box is 17.5 g/cm³.
Answer:
Explanation:
The relation between equilibrium constant and Ecell is given below .
E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K
E⁰cell = 1.46 - 1.21 = .25 V
n = 2
Putting the values
.25 = (8.314 x 298 lnK) / (2 x 96485 )
lnK = 19.47
K = 2.85 x 10⁸
2 )
Change in free energy Δ G
Δ G ⁰ = nE⁰ F
n = 4
E⁰ = .4 + .83 = 1.23 V
Δ G ⁰= 4 x 1.23 x 96485
= 474706 J / mol
3 )
E⁰cell = (RT / nF ) lnK
n = 2
1.78 = 8.314 x 298 lnK / 2 x 96485
lnK = 138.638
K = 1.62 x 10⁶⁰
Mass number is equal to the number of protons plus the number of neutrons in a nucleus of an atom
