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jenyasd209 [6]
3 years ago
9

How many moles of water are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas?

Chemistry
1 answer:
ASHA 777 [7]3 years ago
5 0
How many moles of water at produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas the answer is D
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Pleaseee helpppppppp​
ahrayia [7]

Answer:

Potassium

1s2 2s2 2p6 3s2 3p6 4s1

Explanation:

The atom having only one electron its outermost shell must belong to an element in group one of the periodic table.

Having noted that, we proceed to find out what element in group one that has the atom just described in the question.

That atom must belong to an element in the fourth period. The only group 1 element in the fourth period is potassium.

The electron configuration of potassium is;

1s2 2s2 2p6 3s2 3p6 4s1

6 0
3 years ago
Can you please help me with my homework this is due in 4 minutes!! Have a nice day!! :)))
Greeley [361]

Answer:

I'd answer, but I dont really know what it's talking about.

Explanation:

The process of making glass involves a chemical change. While a physical change describes change in the superficial properties of a substance-- like melting ice into water, or tearing up a piece of paper-- a chemical change alters the chemical makeup of the substance itself. Glass can undergo physical changes, too!

3 0
3 years ago
How much sodium bicarbonate to raise alkalinity in pool.
almond37 [142]

Answer:

A rule of thumb is that 1.5 lbs. of baking soda per 10,000 gallons of water will raise alkalinity by about 10 ppm. If your pool's pH is tested below 7.2, add 3-4 pounds of baking soda. If you're new to adding pool chemicals, start by adding only one-half or three-fourths of the recommended amount.

4 0
1 year ago
Part 1: What is the final volume in milliliters when 0.730 L of a 44.8 % (m/v) solution is diluted to 23.3 % (m/v)?
Andre45 [30]

part 1 : the final volume : 1.404 L

part 2 : the initial concentration : 4.06 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

part 1 :

M₁=44.8%

V₁=0.73 L

M₂=23.3%

\tt V_2=\dfrac{M_1.V_1}{M_2}\\\\V_2=\dfrac{44.8\times 0.73}{23.3}\\\\V_2=1.404~L

part 2 :

V₁=739 ml=0.739 L

V₂=1.5 L

M₂=2

\tt M_1=\dfrac{M_2.V_2}{V_1}\\\\M_1=\dfrac{2\times 1.5}{0.739}\\\\M_1=4.06

6 0
3 years ago
What is Wesley Harris, the writer of this account, trying to escape​
4vir4ik [10]

Answer:

Slavery.

Explanation:

6 0
3 years ago
Read 2 more answers
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