The answer is that (It’s 6.6)
Answer:Consider the Set A = {X | X is an even whole number between 0 and 2 } = .
Since, whole numbers are the set of numbers starting from zero upto infinity.
Even numbers are the numbers which are exactly divisible by '2'.
So, we have to find the even whole number between 0 and 2.
Since, only '1' is a whole number between 0 and 2 which is not an even number as '1' is not divisible by '2'.
Therefore, there is no even whole number between 0 and 2.
So, this set is empty.
Therefore, A = { X | X is an even whole number between 0 and 2} =
Step-by-step explanation:
Answer:
24 units
Step-by-step explanation:
Given is a circle with two chord BE and CD
BE and CD intersect at A
By circle chords intersection theorem we have
DA*AC = EA*AB
i.e. 8(15) = 5(AB)
Divide by 5 both the sides
AB =8(15)/5 = 8(3) = 24 units
Verify:
Let us check now whether chord intersection theorem is satisfied.
DA*AC = 8(15) = 120
EA*AB = 5(24) = 120
Since these two equal, we verify that answer is right.
1. Original equation
2.Distributive property
3. Add 6x to each side
4. Subtract 2 from each side
5. Divide each side by 11
