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Marizza181 [45]
3 years ago
5

68=u-11 need help lololo

Mathematics
2 answers:
dem82 [27]3 years ago
8 0

Answer:

79

Step-by-step explanation:

79-11=68

i hope this helps

Gnom [1K]3 years ago
5 0

Answer:

U=79

68+11=79

79=U

U=79

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Can someone help with this?
Lana71 [14]

Answer:

72.1 cm

Step-by-step explanation:

The arc length formula is s = rФ, where Ф is the central angle and is in radians (not degrees).

Here we convert 140° to radians:  140°(π/180°) = 2.44 radians.

Then the desired arc length is s = rФ = (29.5 cm)(2.44 radians) = 72.1 cm

7 0
3 years ago
Written as a simplified polynomial in standard form, what is the result when
kompoz [17]

2x-8 - (2x+7)^2\\\\=2x-8 -(4x^2 + 2\cdot 2x \cdot 7 + 7^2)\\\\=2x-8-(4x^2 + 28x +49)\\\\=2x - 8 -4x^2-28x -49\\\\=-4x^2 -26x -57\\\\

8 0
2 years ago
Lois and Clark own a company that sells wagons.The amount they pay each of their sales employees (in dollars) is given by the ex
Karolina [17]
12h + 30w represents the amount paid to each employee.....where h is the number of hrs and w is the number of wagons sold.

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12h + 30w = total pay
12(6) + 30(3) =
72 + 90 =
162 = total pay <===


8 0
3 years ago
Henry is working on a division problem. Which decimal point is in the correct place for Henry’s result?
Dominik [7]
It would be answer 4 because 14.85 divided by .05 is 297


7 0
3 years ago
A new car is purchased for 22400 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year , how
m_a_m_a [10]

Answer:

t= 12.9 years

Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

Value after t years= $5000

Initial value = $22,400

r= depreciation rate = 11%

t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

= 12.87

t= 12.9 years

5 0
3 years ago
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