Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
If this is correct the answer would be
y^2 + 0.1y + 0.0025
Answer:
et's solve for x.
5y−4x=−72y+4z
Step 1: Add -5y to both sides.
−4x+5y+−5y=−72y+4z+−5y
−4x=−77y+4z
Step 2: Divide both sides by -4.
−4x
−4
=
−77y+4z
−4
x=
77
4
y−z
Answer:
x=
77
4
y−z
Let's solve for y.
5y−4x=−72y+4z
Step 1: Add 72y to both sides.
−4x+5y+72y=−72y+4z+72y
−4x+77y=4z
Step 2: Add 4x to both sides.
−4x+77y+4x=4z+4x
77y=4x+4z
Step 3: Divide both sides by 77.
77y
77
=
4x+4z
77
y=
4
77
x+
4
77
z
Answer:
y=
4
77
x+
4
77
z
Step-by-step explanation:
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Answer:
20
Step-by-step explanation:
6 + 2 = 8
8 + 3 = 11
11 + 4 =15
15 + 5 =20
How far would the cheetah have traveled in the first eight minutes? show how you arrived at your answer
