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777dan777 [17]
3 years ago
7

In a redox reaction, what happens to a substance’s charge when it is oxidized?

Chemistry
2 answers:
vivado [14]3 years ago
4 0
Oxidation is the loss of electrons, therefore a substance's charge will increase
VMariaS [17]3 years ago
3 0
Oxdineiez it becomes more reactive
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In which natural cycle must an important gas in Earth's atmosphere be fixed before plants can use it?
Maru [420]
The answer is C . nitrogen cycle
5 0
2 years ago
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Read the quote: "No tears in the writer, no tears in the reader." Which best explains the meaning of this quote?​
liubo4ka [24]

Answer:

From personal experience

Explanation:

If is not felt by the writer, the reader will not feel it either!

8 0
2 years ago
Help pls! thank u (:
alexgriva [62]

Answer:

7.65 moles of silver are produced

Explanation:

Zinc, Zn, reacts with silver nitrate, AgNO3, as follows:

Zn + 2AgNO3 → Zn(NO3)2 + 2Ag

<em>Where 1 mole of Zn reacts with an excess of AgNO3 to produce 2 moles of Ag</em>

To solve this question we must convert the mass of Zn to moles and, using the chemical equation, we can find the moles of Ag as follows:

<em>Moles Zn (Molar mass: 65.38g/mol):</em>

250g Zn * (1mol / 65.38g) = 3.824 moles Zn

<em>Moles Ag:</em>

3.824 moles Zn * (2mol Ag / 1mol Zn) =

<h3>7.65 moles of silver are produced</h3>
7 0
2 years ago
How many moles of hydrogen are in the sample?<br> Round your answer to 4 significant digits.
finlep [7]

Answer:

1.56 mol H₂

Explanation:

Mg₃(Si₂O₅)₂(OH)₂

<em>There are 4 Si moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>. With that in mind we can <u>calculate how many Mg₃(Si₂O₅)₂(OH)₂ moles are there in the sample</u>, using the <em>given number of silicon moles</em>:

  • 3.120 mol Si * \frac{1molMg_3(Si_2O_5)_2(OH)_2}{4molSi} = 0.78 mol Mg₃(Si₂O₅)₂(OH)₂

Then we can <u>convert Mg₃(Si₂O₅)₂(OH)₂ moles into hydrogen moles</u>, keeping in mind that <em>there are 2 hydrogen moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>:

  • 0.78 mol Mg₃(Si₂O₅)₂(OH)₂ * 2 = 1.56 mol H₂
8 0
3 years ago
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ
Lelechka [254]

Answer:

ΔG°rxn = -69.0 kJ

Explanation:

Let's consider the following thermochemical equation.

N₂O(g) + NO₂(g) → 3 NO(g) ΔG°rxn = -23.0 kJ

Since ΔG°rxn < 0, this reaction is exergonic, that is, 23.0 kJ of energy are released. The Gibbs free energy is an extensive property, meaning that it depends on the amount of matter. Then, if we multiply the amount of matter by 3 (by multiplying the stoichiometric coefficients by 3), the ΔG°rxn will also be tripled.

3 N₂O(g) + 3 NO₂(g) → 9 NO(g) ΔG°rxn = -69.0 kJ

8 0
3 years ago
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