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shepuryov [24]
4 years ago
12

Most water on earth is in which form

Chemistry
2 answers:
Westkost [7]4 years ago
5 0
Water is a simple compound, made of two atoms of hydrogen and one atom of oxygen bonded together.  On land, water is also common: it swirls and meanders through streams, falls from the sky, freezes into snow flakes, and even makes up most of you and me. In this chapter, we'll look at the distribution of water on Earth, and also examine some of its unique properties.<span>

</span>
dem82 [27]4 years ago
4 0
Liquid, because of all the oceans and seas.
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How many significant figures are in 0.08260 L? 4 5 6
mars1129 [50]

Answer:

5

Explanation:

Count the digits after the first non zero number, any number after that (even zero) counts.

Hope that helped!!! k

6 0
3 years ago
Read 2 more answers
AgI + KNO3<br>What type of reaction is this?
emmasim [6.3K]

Answer:

double replacement

Explanation:

4 0
3 years ago
PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
Contact [7]

Answer:

The pH of the solution is 11.48.

Explanation:

The reaction between NaOH and HCl is:

NaOH  +  HCl  →  H₂O  +  NaCl

From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:

n_{NaOH}} = n_{i_{NaOH}} - n_{HCl} = 3.60 \cdot 10^{-3} moles - 5.95 \cdot 10^{-4} moles = 3.01 \cdot 10^{-3} moles

Now, we need to find the concentration of the OH⁻ ions.

[OH^{-}] = \frac{n_{NaOH}}{V}

Where V is the volume of the solution = 1.00 L                

[OH^{-}] = \frac{n_{NaOH}}{V} = \frac{3.01 \cdot 10^{-3} moles}{1.00 L} = 3.01 \cdot 10^{-3} mol/L

Finally, we can calculate the pH of the solution as follows:

pOH = -log([OH^{-}]) = -log(3.01 \cdot 10^{-3}) = 2.52

pH + pOH = 14

pH = 14 - pOH = 14 - 2.52 = 11.48

Therefore, the pH of the solution is 11.48.

I hope it helps you!

3 0
3 years ago
Describe the changes in properties (from metals to nonmetals or from nonmetals to metals) as we move (a) down a periodic group a
defon

Answer:

Explanation:

The changes in properties from metals to non-metals on a periodic table can be measured and determined by the metallicity or electropositivity of elements.

Metallicity is a measure of the tendency of atoms of an element to lose electrons.

a.

Down a periodic group, metallicity increases.

b.

Across a period from left to right electropositivity or metallicity decreases.

Metals are found in the left part of periodic table and the most reactive metal sits in the lower left corner. Non-metals are towards the right side of the table.

7 0
3 years ago
A sample of H2 gas (12.28 g) occupies 100.0 L at 400.0 K and 2.00 atm. A sample weighing 9.49 g occupies ________ L at 353 K and
lutik1710 [3]

Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, you know:

  • P= 2 atm
  • V= ?
  • n= 9.49 gramsx\frac{1 mole}{2 grams} = 4.745moles being 2g/mole  the molar mass of H2, that is, the amount of mass that a substance contains in one mole.
  • R= 0.082 \frac{atmL}{molK}
  • T= 353 K

Replacing:

2 atm× V = 4.745 moles× 0.082\frac{atmL}{molK}× 353 K

Solving:

V = (4.745 moles× 0.082\frac{atmL}{molK}× 353 K)÷ 2 atm

<u><em>V= 68.67 L</em></u>

Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Learn more:

  • brainly.com/question/4147359?referrer=searchResults
5 0
3 years ago
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