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2 answers:
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Answer: a) Volume of = 19.2 L
b) volume of = 20.8 Liters
Explanation:
Combustion is a type of chemical reaction in which fuel is reacted with oxygen to form carbon dioxide and water.
To calculate the moles, we use the equation:
a) Volume of
According to stoichiometry:
1 mole of glucose require = 6 moles of oxygen
Thus 0.131 moles of glucose require = moles of oxygen
According to the ideal gas equation:'
P = Pressure of the gas = 1.00 atm
V= Volume of the gas = ?
T= Temperature of the gas = 298 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= 0.783
Thus volume of oxygen required is 19.2 Liters
b) Volume of
According to stoichiometry:
1 mole of glucose produce = 6 moles of
Thus 0.131 moles of glucose require = moles of
According to the ideal gas equation:
P = Pressure of the gas = 0.960 atm
V= Volume of the gas = ?
T= Temperature of the gas = =310 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= 0.783
Thus volume of produced is 20.8 Liters