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Pie
3 years ago
10

How many total atoms are in 0.920 g of P2O5?

Chemistry
2 answers:
lions [1.4K]3 years ago
8 0
Molar mass P2O5 = 31 x 2 + 16 x 5 => 142 g/mol


142 g ---------------- 6.02 x 10²³ molecules
0.920g g ------------ ( molecules )

molecules = 0.920 x ( 6.02 x 10²³ ) / 142

molecules = 5.53 x 10²³ / 142

= 3.89 x 10²¹ molecules

1 molecule P2O5 -------------------------- 7 atoms
3.89 x 10²¹ molecules -------------------- ( atoms )

atoms = ( 3.89 x 10²¹) x 7 / 1

atoms = 2.72 x 10²² atoms of P2O5

hope this helps!
SSSSS [86.1K]3 years ago
5 0
Given the mass of a compound, the total number of atoms can be determined by converting first the mass to moles and then multiplying the moles to Avogadro's number (6.022 x 10^23 atoms/mole). In this case, the answer is 3.9 x10^21 atoms
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5 0
3 years ago
What is 10 times as many as 1 hundred is blank hundred or blank thousand ?
Rama09 [41]

10 times as many as 1 hundred is 10 hundred or 1 thousand.

This is the question of simple multiplications related to a place value system.

The given equation in unit form can be rewritten as:

10 × 1 × 100 = (X × 100) or (Y × 1000)

Arranging in two parts, we get,

10 × 1 × 100 = X × 100           ........(1)

10 × 1 × 100 = Y × 1000         ........(2)

Now, calculating the value of X and Y,

From equation (1), we get,

10 × 1 × 100 = X×100

or, 1000 = X × 100

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Hence, 10 times as many as 1 hundred is 10 hundred.

Similarly, from equation (2). we get,

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or, 1000 = Y × 1000

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Hence, 10 times as many as 1 hundred is 1 thousand.

Therefore, 10 times as many as 1 hundred is 10 hundred or 1 thousand.

To learn more about hundreds, thousands, and place values, visit: brainly.com/question/17785584

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8 0
1 year ago
Please help. thank youuuu
Dmitry [639]

Answer:

'See Explanation

Explanation:

Determine the [OH−] , pH, and pOH of a solution with a [H+] of 9.5×10−13 M at 25 °C.

Given [H⁺] = 9.5 x 10⁻¹³M => [H⁺][OH⁻] = 1.0 x 10⁻¹⁴ => [OH⁻] = 1.0 x 10⁻¹⁴/9.5 x 10⁻¹³ = 0.0105M

pH = -log[H⁺] = -log(9.5 x 10⁻¹³) = - (-1202) = 12.02.

pOH = -log[OH⁻] = -log(0.0105) = -(-1.98) = 1.98

Now you use the same sequence in the remaining problems.

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