2 years ago

Anyone help me do this question.. am giving the brainliest

Physics

1 answer:

mr_godi [17]2 years ago

5 0

Answer:

(i)9 cm

(ii)20 cm

(iii)3 mm

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Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. The initial temperature of the gas is 28.0

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Answer:

63.5 °C

Explanation:

The expression for the calculation of work done is shown below as:

$w=P\times \Delta V$

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Also,

Considering the ideal gas equation as:-

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

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So,

$V=\frac{nRT}{P}$

Also, for change in volume at constant pressure, the above equation can be written as;-

$\Delta V=\frac{nR\times \Delta T}{P}$

So, putting in the expression of the work done, we get that:-

$w=P\times \frac{nR\times \Delta T}{P}=nR\times \Delta T$

Given, initial temperature = 28.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (28.0 + 273.15) K = 301.15 K

W=1770 J

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Thus,

$T_2=301.15\ K+\frac{1770}{6\times 8.314}\ K$

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The final temperature is:- 63.5 °C

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