Answer:
1000 N
Explanation:
The magnitude of the electrostatic force between two charged object is given by
where
k is the Coulomb constant
q1, q2 is the magnitude of the two charges
r is the distance between the two objects
Moreover, the force is:
- Attractive if the two forces have opposite sign
- Repulsive if the two forces have same sign
In this problem:
are the two charges
r = 3000 m is their separation
Therefore, the electric force between the charges is:
Answer:
v =3.41 m/s
Explanation:
given,
mass of block 1 = 6 Kg
mass of another block 2 = 4 Kg
coefficient of friction = 0.3
Assuming 6 Kg block is attached to the spring of spring constant 350 N/m
and distance between the two block is equal to 0.5 m
using formula
U = 43.75 J
using conservation of energy
KE = U - f.d
where f is the frictional force acting
v =3.41 m/s
Explanation:
Spring tides generally occur twice a month—during new and full moons, when the Earth, Sun, and Moon line up in a row. In this arrangement, the gravities of the Sun and Moon work together and have the strongest pull on Earth. This produces the largest difference between high and low tide.
Spring Tides
During full moon or new moon phases, the gravitational forces of the Sun and Moon are maximized, producing very large ranges of tidal highs and lows called spring tides
True
<span> An object at rest stays at rest and an object in
motion stays in motion with the same speed and in the same direction
unless acted upon by an unbalanced force.this is newtons first law</span>
Answer:
Explanation:
mass of electron in amu = .000549
mass of electron = mass of proton
total mass of electron and proton = 2 x1.098 x 10⁻³ = 2.196 x 10⁻³ amu
1 amu = 931 x 10⁶ eV
2.196 X 10⁻³ amu = 2.196 x 931 x 10³ eV
= 2.044 X 10⁶ eV.
= 2044 X 10³ ev
So minimum energy required = 2044 x 10³ eV.
Wavelength of photon required = 12375/2044 x 10³ A
= 6.054 X 10⁻³A. =6.054 X 10⁻¹³ m
frequency of photon = 3 x 10⁸/6.054x 10⁻¹³
= .4955 x 10¹⁶Hz.
= 4.955 x 10¹⁵ Hz
