Answer:
T= 38.38 N
Explanation:
Here
mass of can = m = 3 kg
g= 9.8 m/sec2
angle θ = 40°
From figure we see the vertical and horizontal component of tension force T
If the can is to slip - then horizontal component of tension force should become equal to force of friction.
First we find force of friction
Fs= μ R
where
μ = 0.76
R = weight of can = mg = 3 × 9.8 = 29.4 N
Now horizontal component of tension
Tx= T cos 40 = T× 0.7660 N
==>T× 0.7660 = 29.4
==> T= 38.38 N
Tension in the rope due to applied force will be given as

angle of applied force with horizontal is 37 degree
displacement along the floor = 6.1 m
so here we can use the formula of work done

now we can plug in all values above


So here work done to pull is given by 691.8 J
Electron volts...........
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<span>When a seed or plant is said to be inactive, it is dormant. Dormancy occurs when <span>a plant reduces its metabolic activity.</span></span>