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2 years ago

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A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len

gth?
A. 2.3 N
B. 1.5 N
C. 75 N
D. 3750 N

1 answer:

ale4655 [162]2 years ago

7 0

Answer:

(75 x 0.02) = 1.5 N

Explanation:

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A certain car battery with a 12.0 V emf has an initial charge of 131 A · h. Assuming that the potential across the terminals sta

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Answer:

The battery can supply 130 W for 11.75 h

Explanation:

In order to discover the time in wich the battery can supply this energy we need to find how much current is being drawn from it, we do that by using the equation for real power that is P = V*I, since we have V and P we can solve for I as seen bellow:

I = P/V = 130/12 = 10.834 A

We can use this value to find how many hours the power can supply said current. We do that by dividing the current capacity of the battery by the current drawn:

t = 141/12 = 11.75 h

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The acquisition of electric charge without contact between charged and/or uncharged substances.

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Answer:

induction

Explanation:

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The plum pudding model of the atom states that

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Answer:

According to this model, the atom is a sphere of positive charge, and negatively charged electrons are embedded in it to balance the total positive charge.

Explanation:

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3 years ago

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An unknown radioactive sample is observed to decrease in activity by a factor of two in a one hour period. What is its half-life

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Answer:

The half-life is $t_{1/2} = 1.005 h$

Explanation:

Using the decay equation we have:

$A=A_{0}e^{-\lambda t}$

Where:

λ is the decay constant
A(0) the initial activity
A is the activity at time t

We know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that $A = \frac{A_{0}}{2}$

$\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}$

$0.5=e^{-\lambda*1 h}$

Taking the natural logarithm on each side we have:

$ln(0.5)=-\lambda$

$\lambda=0.69 h^{-1}$

Now, the relationship between the decay constant λ and the half-life t(1/2) is:

$\lambda = \frac{ln(2)}{t_{1/2}}$

$t_{1/2} = \frac{ln(2)}{\lambda}$

$t_{1/2} = \frac{ln(2)}{0.69}$

$t_{1/2} = 1.005 h$

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2 years ago

3B with worked out equations please

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Answer:

b) 1500N

c) to the right

Explanation:

Resultant force= 2000 -500= 1500N

Resultant force is a combination of 2 or more forces acting on an object.

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