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vitfil [10]
3 years ago
13

A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len

gth?
A. 2.3 N
B. 1.5 N
C. 75 N
D. 3750 N
Physics
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

(75 x 0.02) = 1.5 N

Explanation:

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Answer:

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Explanation:

Here

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angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

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Tx= T cos 40 = T× 0.7660  N

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