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vitfil [10]
3 years ago
13

A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len

gth?
A. 2.3 N
B. 1.5 N
C. 75 N
D. 3750 N
Physics
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

(75 x 0.02) = 1.5 N

Explanation:

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Answer:

R=m*g-∀fl*g*l3

Explanation:

<em>An iron block of density rhoFe and of volume l 3 is immersed in a fluid of density rhofluid. The block hangs from a scale which reads W as the weight. The top of the block is a height h below the surface of the fluid. The correct equation for the reading of the scale is</em>

From Archimedes' principle we know that a body when immersed in a fluid, fully or partially, experiences an the upward buoyant force equal to the weight of the fluid displaced. As the body is fully submerged in water, volume of water displaced  

density of iron =mass/ volume

rho=m/l3

mass=rhol3

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R=w-F

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6 0
3 years ago
what is the force of gravity attraction between an object with a mass of 0.5 kg and another object has a mass of 0.33 kg and a d
elena55 [62]

Answer:

from \: newton \: law \: of \: gravitation \\ F =  \frac{GMm}{ {r}^{2} }  \\ G = 6.67 \times  {10}^{ - 11}  \\ M = 0.5 \: kg \\ m = 0.33 \: kg \\ r = 0.002 \: m \\ substitute \\ F =  \frac{(6.67 \times  {10}^{ - 11}) \times (0.5) \times (0.33)) }{ {(0.002)}^{2} }  \\  = 2.75 \times  {10}^{ - 6} N

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False. Since the forces are pulling in equal and opposite directions, the net force is 0.
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