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Lapatulllka [165]
2 years ago
7

The squared paper shows the nets of cuboid A and cuboid B.

Mathematics
1 answer:
kompoz [17]2 years ago
4 0

Answer:

No they don't.

LINK TO PICTURE  OF WORK - My uploads aren't working my apologies.

https://tex.z-dn.net/?f=A%3A%5C%5C(2*2*2)%2B(3*2*2)%2B(3*2*2)%3D%5C%5C(4*2)%2B(6*2)%2B(6*2)%3D%5C%5C8%2B12%2B12%3D%5C%5C20%2B12%3D%5C%5C32%20cm%5E2%5C%5C%5C%5CB%3A%5C%5C(1*3*2)%2B(1*4*2)%2B(3*4*2)%3D%5C%5C(3*2)%2B(4*2)%2B(12*2)%3D%5C%5C6%2B8%2B24%3D%5C%5C14%2B24%3D%5C%5C38%20cm%5E2

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Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
5 0
2 years ago
The width of a rectangle is 22 inches and the perimeter is at least 165 inches. what inequality could be used to find the minimu
Lera25 [3.4K]
The answer is D.

We know that a rectangle has two widths that are equal and two lengths that are equal. One width is 22, so the other one is also 22.

If you wanted to find the lengths, you would add both widths together (same as multiplying a width by two) and add that to the two lengths equaled to the perimeter.

So, 22 * 2 + 2x = perimeter of rectangle. We added all four sides together.

We know that the perimeter is at least 165, so 22 * 2 + 2x = 165. Here's the twist. They want the most minimum possible length. So, what answer choice gives you 165 or less for the most minimum or smallest length while still getting to 165?
That is D.
22 * 2 + 2x < = 165.
Hope this helped!
6 0
3 years ago
Read 2 more answers
Xsquared+11x+28+xsquared+13x+40
UNO [17]
X² + 11x + 28 + x² + 13x + 40

combine like terms

x² + x² = 2x²
11x + 13x = 24x
28 + 40 = 68

2x² + 24x + 68 is your answer

if you want it simplified: 

2(x² + 12x + 34)
   

hope this helps


5 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
wel

Answer:

z=\frac{15\sqrt{3}}{2}

Step-by-step explanation:

In leftmost triangle:

opposite side =y

adjacent=a

now, we can use trig formula

tan(60)=\frac{y}{a}

now, we can solve for y

y=atan(60)

In rightmost triangle:

adjacent=b

opposite=y

a+b=15

b=15-a

now, we can use trig formula

tan(30)=\frac{y}{15-a}

now, we can solve for y

y=(15-a)tan(30)

now, we can set them equal

and then we can solve for a

atan(60)=(15-a)tan(30)

\sqrt{3}a\cdot \:3=\frac{\sqrt{3}\left(15-a\right)}{3}\cdot \:3

4\sqrt{3}a=15\sqrt{3}

a=\frac{15}{4}

now, we can find b

b=15-\frac{15}{4}

b=\frac{45}{4}

now, we can use trig formula

cos(30)=\frac{b}{z}

now, we can find z

z=\frac{\frac{45}{4}}{cos(30)}

we can simplify it

and we get

z=\frac{15\sqrt{3}}{2}


4 0
3 years ago
PLEASE HELLPPPPPPP!!!!!!
pochemuha
Company A would because it is the least with the lowest slope since it is not increasing very fast

8 0
2 years ago
Read 2 more answers
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