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Lapatulllka [165]
2 years ago
7

The squared paper shows the nets of cuboid A and cuboid B.

Mathematics
1 answer:
kompoz [17]2 years ago
4 0

Answer:

No they don't.

LINK TO PICTURE  OF WORK - My uploads aren't working my apologies.

https://tex.z-dn.net/?f=A%3A%5C%5C(2*2*2)%2B(3*2*2)%2B(3*2*2)%3D%5C%5C(4*2)%2B(6*2)%2B(6*2)%3D%5C%5C8%2B12%2B12%3D%5C%5C20%2B12%3D%5C%5C32%20cm%5E2%5C%5C%5C%5CB%3A%5C%5C(1*3*2)%2B(1*4*2)%2B(3*4*2)%3D%5C%5C(3*2)%2B(4*2)%2B(12*2)%3D%5C%5C6%2B8%2B24%3D%5C%5C14%2B24%3D%5C%5C38%20cm%5E2

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If f(x)=7-3x and g(x)=3x-7, what is the value of f(1)+g(1)?
kondor19780726 [428]
F(x)=7-3x g(x)=3x-7

First let’s solve for f(1)

f(1)= 7-3(1)

f(1)= 7-3

f(1)= 4 *we will save this for later

Let’s now solve for g(1)

g(1)= 3(1)-7
g(1)= 3-7
g(1)= -4

Now we can find f(1) + g(1)

f(1) =4 and g(1)= -4

4+(-4) = 0








5 0
3 years ago
Sin(x−y)/sinxsiny= coty - cotx<br>​
andrew-mc [135]

x = 0 \\  \\  \sin^{2}(y) \sin( \frac{x - y}{ \sin(x)} ) -  \sin(x)  \cos(y)\cos(x)\sin(y)= 0

4 0
3 years ago
The functions u and w are defined as follows. u(x)=2x-2 w(x)=-2x^2+1 Find the value of w(u(5)).
lianna [129]

Answer:

-127

Step-by-step explanation:

u(x)=2x-2

w(x)= -2x^2+1

w(u(5))=?

---------

u(5)= 2*5-2= 8

W(8)= - 2*64+1= -127

8 0
3 years ago
Solve for <br> x<br> 6<br> (<br> x<br> −<br> 6<br> )<br> =<br> 5<br> (<br> x<br> +<br> 1<br> )
prisoha [69]

Answer:

x = 41

Step-by-step explanation:

6(x−6)=5(x+1)

Step 1 - Expand the brackets:

6(x - 6) = 5(x + 1)

6x - 36 = 5x + 5

Step 2 - Add 36 to both sides of the equation:

6x - 36 + 36 = 5x + 5 + 36

6x = 5x + 41

Step 3 - Subtract 5x from both sides of the equation:

6x - 5x = 5x + 41 - 5x

x = 41

Hope this helps!

8 0
2 years ago
Read 2 more answers
A polygon ABCD is inscribed in a circle. Find m angle D A B.
Natali5045456 [20]

Answer: \Large\boxed{\angle DAB=62^\circ}

Concept:

Here, we need to know about the idea of a cyclic quadrilateral.

In a <u>cyclic quadrilateral</u>, the sum of either pair of opposite angles is supplementary, which means they add up to 180°.

Please refer to the attachment below for a graphical explanation

Solve:

<u>Given information</u>

∠DAB = 2x + 4

∠ABC = 4y + 4

∠BCD = 4x + 2

∠CDA = 3y + 8

<u>Derived formula from the concept</u>

∠DAB + ∠BCD = 180°

∠ABC + ∠CDA = 180° (Not Important)

<u>Substitute values into the formula that includes ∠DAB</u>

∠DAB + ∠BCD = 180°

(2x + 4) + (4x + 2) = 180

<u>Combine like terms</u>

2x + 4 + 4x + 2 = 180

2x + 4x + 4 + 2 = 180

6x + 6 = 180

<u>Subtract 6 on both sides</u>

6x + 6 - 6 = 180 - 6

6x = 174

<u />

<u>Divide 6 on both sides</u>

6x / 6 = 174 / 6

x = 29

<u>Substitute values into the angle expression of ∠DAB</u>

∠DAB = 2x + 4

∠DAB = 2 (29) + 4

∠DAB = 58 + 4

\Large\boxed{\angle DAB=62^\circ}

Hope this helps!! :)

Please let me know if you have any questions

5 0
1 year ago
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