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Zielflug [23.3K]
3 years ago
7

How can chemical symbols prove that cubic zirconia is not a diamond?

Chemistry
2 answers:
wlad13 [49]3 years ago
8 0

Answer:

Diamond is pure carbon, C

Zircona is zirconium oxide, ZrO_{2}

Explanation:

Chemical symbols are used to distinguish one atom (or molecule) from the other.

Diamond is composed of pure carbon (C) where each C atom is bonded to four other C atoms forming a repeating network of tetrahedrally linked C atoms. Therefore, the chemical symbol of diamond is C.

If the chemical symbol of zircona were also 'C' then it would prove that both are identical. However, zircona is essentially zirconium oxide which has a chemical formula, ZrO_{2}. Therefore, the different symbols suggest that the two are not identical.

Zigmanuir [339]3 years ago
3 0

One compound can be differentiate from other by its composition although both look same. The diamond has the chemical formula of carbon (c) as it is a repeating unit of carbon which has shining features. On the other hand zirconia is zirconium dioxide (ZrO_{2}. When it is crystallized it becomes shiny as like diamond. However the look of the two are meanwhile similar the composition is totally different as well the molar mass.

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Calculate the maximum volume in ml of 0.15M HCl that each of the following antacid formulations would be expected to neutralize.
vlada-n [284]

a. 34 mL; b. 110 mL

a. A tablet containing 150 Mg(OH)₂


Mg(OH)₂ + 2HCl ⟶ MgCl₂ + 2H₂O


<em>Moles of Mg(OH)₂</em> = 150 mg Mg(OH)₂ × [1 mmol Mg(OH)₂/58.32 mg Mg(OH)₂

= 2.572 mmol Mg(OH)₂


<em>Moles of HCl</em> = 2.572 mmol Mg(OH)₂ × [2 mmol HCl/1 mmol Mg(OH)₂]

= 5.144 mmol HCl


Volume of HCl = 5.144 mmol HCl × (1 mmol HCl/0.15 mmol HCl) = 34 mL HCl


b. A tablet containing 850 mg CaCO₃


CaCO₃ + 2HCl ⟶ CaCl₂ + CO₂ + H₂O


<em>Moles of CaCO₃</em> = 850 mg CaCO₃ × [1 mmol CaCO₃/100.09 mg CaCO₃

= 8.492 mmol CaCO₃


<em>Moles of HCl</em> = 8.492 mmol CaCO₃ × [2 mmol HCl/1 mmol CaCO₃]

= 16.98 mmol HCl


Volume of HCl = 16.98 mmol HCl × (1 mL HCl/0.15 mmol HCl) = 110 mL HCl


5 0
3 years ago
if 20.2g of NO and 13.8g of O2 are used to form NO2, how many moles of excess reactant will be left over
ruslelena [56]

Answer:

0.095 moles of O₂ are left over.

Explanation:

First of all, state the balanced reaction:

2NO + O₂ → 2NO₂

We determine moles of each reactant:

20.2 g . 1mol / 30g =  0.673 moles of NO

13.8g . 1mol / 32g = 0.431 moles of oxygen

Oxygen is the excess reactant. Let's see.

For 2 moles of NO I need 1 mol of O₂

Then, for 0.673 moles of NO I may use (0.673 .1) /2 = 0.336 moles

I have 0.431 moles of O₂ and I only need 0.336 mol. According to reaction, stoichiometry is 2:1.

In conclussion, the moles of excess reactant that will be left over:

0.431 - 0.336 = 0.095 moles

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3 years ago
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