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Zielflug [23.3K]
3 years ago
7

How can chemical symbols prove that cubic zirconia is not a diamond?

Chemistry
2 answers:
wlad13 [49]3 years ago
8 0

Answer:

Diamond is pure carbon, C

Zircona is zirconium oxide, ZrO_{2}

Explanation:

Chemical symbols are used to distinguish one atom (or molecule) from the other.

Diamond is composed of pure carbon (C) where each C atom is bonded to four other C atoms forming a repeating network of tetrahedrally linked C atoms. Therefore, the chemical symbol of diamond is C.

If the chemical symbol of zircona were also 'C' then it would prove that both are identical. However, zircona is essentially zirconium oxide which has a chemical formula, ZrO_{2}. Therefore, the different symbols suggest that the two are not identical.

Zigmanuir [339]3 years ago
3 0

One compound can be differentiate from other by its composition although both look same. The diamond has the chemical formula of carbon (c) as it is a repeating unit of carbon which has shining features. On the other hand zirconia is zirconium dioxide (ZrO_{2}. When it is crystallized it becomes shiny as like diamond. However the look of the two are meanwhile similar the composition is totally different as well the molar mass.

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7. Disulfur dichloride can be made by reacting chlorine gas with molten sulfur. What is the yield of S2Cl2 expected in a laborat
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Answer:

11.4g of S₂Cl₂ is the expected yield

9.69g of S₂Cl₂ are produced with a 85% yield

Explanation:

The reaction of sulfur S₈ with Cl₂ to produce S₂Cl₂ is:

S₈ + 4Cl₂ → 4S₂Cl₂

<em>Where 1 mole of sulfur reacts with four moles of chlorine to produce four moles of disulfur dichloride.</em>

To find the limiting reactant you need to convert mass of each reactant to moles using its molar mass, thus:

S₈ (Molar mass: 256.52g/mol): 10.0g ₓ (1mol / 256.52g) = 0.0390 moles S₈

Cl₂ (Molar mass: 70.9g/mol): 6.00g ₓ (1mol / 70.9g) = 0.0846 moles Cl₂

For a complete reaction of 0.0390 moles of sulfur, there are necessaries:

0.0390 mol S₈ ₓ (4 mol Cl₂ / 1 mol S₈) = <em>0.156 moles Cl₂. </em>As you have just 0.0846 moles of chlorine, Cl₂ is the limiting reactant.

As 4 moles of Cl₂ produce 4 moles of S₂Cl₂.<em> 0.0846 moles of Cl₂ produce, in theory, 0.0846 moles of S₂Cl₂ (Molar mass: 135.04g/mol). </em>In mass:

0.0846 moles S₂Cl₂ ₓ (135.04g/mol) =

<h3>11.4g of S₂Cl₂ is the expected yield</h3>

If you produce just the 85.0% of yield, mass of S₂Cl₂ is:

11.4g ₓ 85% =

<h3>9.69g of S₂Cl₂</h3>
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