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3 years ago

Given the incomplete equation for the combustion of ethane:

Chemistry

2 answers:

andriy [413]3 years ago

5 0

Answer : The correct option is, (4) $(H_2O)$

Explanation :

Combustion reaction : It is a reaction in which a hydrocarbon react with the oxygen gas to produces carbon dioxide as water as a products.

The given incomplete equation are :

$2C_2H_6+7O_2\rightarrow 4CO_2+6_$

In this equation, we see that a hydrocarbon and oxygen gas are present on reactant side and carbon dioxide are present on product side but water molecules are missing on the product side. So, we are adding water $(H_2O)$ on missing side.

The given complete equation will be :

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

Therefore, the formula missing on product is, $(H_2O)$

Svetach [21]3 years ago

3 0

The combustion of ethane will consume oxygen and create carbon dioxide and water. That is a general rule for most alkane, olefin and alkyne. So the missing product is H2O.

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A gas has a volume of 31.2 L at a temperature of 28 degrees Celsius and a pressure of 82.6 kPa. How many moles are in the sample

zhenek [66]

1.02 moles of the gas is present in the sample.

The conditions in which the gases deviate from ideal behavior is high pressure and low temperatures.

Correct option is 2.

Explanation:

Data given:

volume of the gas = 31.2 litres

temperature of the gas = 28 degrees or 301.15 K

pressure of the gas = 82.6 kPa or 0.815 atm

R (Gas constant) = 0.0820 Latm/moles K

number of moles =?

From the ideal gas law, we have

PV = nRT

rearranging the equation:

n = $\frac{PV}{RT}$

n = $\frac{0.815 X 31.2}{301.15 X 0.0820}$

n = 1.02 moles

At high pressure and low temperature an ideal gas deviates from ideal behaviour. Under high pressure the gas molecules get closer to each other and intermolecular force acts on them as molecules attract each other while in ideal case gas has no attractions in its molecules.

5 0

3 years ago

Use Boyle's Law to solve the following problem. A 400 mL sample of a gas is at 10

zubka84 [21]

Answer:

v2 = 100 Ml OR 0.1 Liters

Explanation:

(400 Ml) (10 atm) = (v2) (40 atm)

4000 = 40v2

100 Ml = v2

Liters = ml / 1000

Liters = 100 / 1000

Liters = 0.1

4 0

3 years ago

What is wosutah unsrcambled

horsena [70]

Answer:

Washout?? Outwash??

Explanation:

Girl what-

3 0

2 years ago

Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because

olchik [2.2K]

Answer:

0.3023 M

Explanation:

Let Picric acid = $H_{picric}$

So, $H_{picric}$ + $H_2}O$ ⇄ $H_3}O^+$ + $Picric^-$

The ICE table can be given as:

$H_{picric}$ + $H_2}O$ ⇄ $H_3}O^+$ + $Picric^-$

Initial: 0.52 0 0

Change: - x + x + x

Equilibrium: 0.52 - x + x + x

Given that;

acid dissociation constant ( $K_a$ ) = 0.42

$K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}$

$0.42 = \frac{[x][x]}{0.52-x}}$

$0.42 = \frac{[x]^2}{0.52-x}}$

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x² + 0.42x - 0.2184 = 0 -------------------- (quadratic equation)

Using the quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$ ; ( where +/- represent ± )

= $\frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}$

= $\frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}$

= $\frac{-0.42+\sqrt {1.0496} }{2}$ OR $\frac{-0.42-\sqrt {1.0496} }{2}$

= $\frac{-0.42+1.0245}{2}$ OR $\frac{-0.42-1.0245}{2}$

= $\frac{0.6045}{2}$ OR $-\frac{1.4445}{2}$

= 0.30225 OR - 0.72225

So, we go by the +ve integer that says:

x = 0.30225

x = [ $H_3}O^+$ ] = [ $Picric^-$ ] = 0.3023 M

∴ the value of [H3O+] for an 0.52 M solution of picric acid = 0.3023 M (to 4 decimal places).

6 0

3 years ago

What is the pH of an acid with a [H+] of 1.0 x 10&-4 M? 1. 4 2. 10 3. 1 4. 7

True [87]

PH scale is from 1 to 14 and indicates how acidic or basic a solution is. To find pH or pOH we need to know the H⁺ ion concentration or OH⁻ concentration.
pH can be calculated using the following equation;
pH = -log[H⁺]
the H⁺ concentration of the given acid is 1.0 x 10⁻⁴ M. substituting this we can find the pH
pH = -log[1x10⁻⁴]
pH = 4
answer is 1) 4

3 0

2 years ago