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3 years ago

Given the incomplete equation for the combustion of ethane:

Chemistry

2 answers:

andriy [413]3 years ago

5 0

Answer : The correct option is, (4) $(H_2O)$

Explanation :

Combustion reaction : It is a reaction in which a hydrocarbon react with the oxygen gas to produces carbon dioxide as water as a products.

The given incomplete equation are :

$2C_2H_6+7O_2\rightarrow 4CO_2+6_$

In this equation, we see that a hydrocarbon and oxygen gas are present on reactant side and carbon dioxide are present on product side but water molecules are missing on the product side. So, we are adding water $(H_2O)$ on missing side.

The given complete equation will be :

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

Therefore, the formula missing on product is, $(H_2O)$

Svetach [21]3 years ago

3 0

The combustion of ethane will consume oxygen and create carbon dioxide and water. That is a general rule for most alkane, olefin and alkyne. So the missing product is H2O.

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Given the following unbalanced chemical reaction: As + NaOH Na3AsO3 + H2 What would be the coefficient of the NaOH molecule in t

barxatty [35]

Answer: -

Explanation: -

The given unbalanced chemical equation is As + NaOH -- > Na3AsO3 + H2

We see there 3 sodium on the right side from Na3AsO3.

But there are only 1 sodium on the left from NaOH.

So we multiply NaOH by 3.

As + 3 NaOH -- > Na3AsO3 + H2

Now we see the number of Hydrogen on the left is 3.

But the number of hydrogens is 2 on the left.

So, we multiply to get both sides 6 hydrogen.

As + 6NaOH -- > Na3AsO3 + 3 H2

Rebalancing for Na,

As + 6NaOH -- > 2Na3AsO3 + 3 H2.

Finally balancing As,

2 As + 6 NaOH -- > 2Na3AsO3 + 3H2

The coefficient of the NaOH molecule in the balanced reaction is thus 6

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3 years ago

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Marina86 [1]

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Calculate the molarity of a solution prepared by dissolving 5.850g of solid NaCl in enough water to make 200mL of the solution?

Y_Kistochka [10]

See the attachment below. Thanks :)

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3 years ago

How many grams of NaCl are needed to prepare 50.0 grams of 35.0% of salt solution?

nevsk [136]

Answer:

17.5 g

Explanation:

Given data

Mass of solution to be prepared: 50.0 grams

Concentration of the salt solution: 35.0%

The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.

$50.0gSolution \times \frac{35.0gNaCl}{100gSolution} = 17.5gNaCl$

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3 years ago

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Sliva [168]

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