Mols CuSO4 = M x L = 1.50 x 0.150 = 0.225
<span>mols KOH = 3.00 x 0.150 = 0.450 </span>
<span>specific heat solns = specific heat H2O = 4.18 J/K*C </span>
<span>CuSO4 + 2KOH = Cu(OH)2 + 2H2O </span>
<span>q = mass solutions x specific heat solns x (Tfinal-Tinitial) + Ccal*deltat T </span>
<span>q = 300g x 4.18 x (31.3-25.2) + 24.2*(31.3-25.2) </span>
<span>dHrxn in J/mol= q/0.225 mol CuSO4 </span>
<span>Then convert to kJ/mol
</span>
Answer:
From the graph find the maximum velocity and half it i.e. Vmax/2. Draw a horizontal line from this point till you find the point on the graph that corresponds to it and read off the substrate concentration at that point. This will give the value of Km.
Answer/Explanation:
Wave W is being diffracted, Wave X is being reflected, and waves Y and Z are being refracted.
Answer:
42.3moles
Explanation:
The chemical equation given in this question is as follows:
H2 + O2 → H2O
However, this equation is unbalanced, the balanced chemical equation is as follows:
2H2 + O2 → 2H2O
This equation shows that;
2 moles of hydrogen gas (H2) will produce 2 moles of water (H2O)
Hence, If 42.3 moles of water (H2O) are produced, 42.3 × 2/2
= 42.3moles of hydrogen was reacted.
