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3 years ago

14

As methane burns, it reacts with oxygen and forms carbon dioxide and water. The balanced chemical equation below models this che

mical reaction.

1 answer:

Elan Coil [88]3 years ago

3 0

Explanation:

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What do we assume about the volume of the actual molecules themselves in a sample of gas, compared to the bulk volume of the gas

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We assume that the volume of the molecules themselves in a gas sample is negligible compared to the bulk volume of the gas sample: this helps us to explain why gases are so compressible.

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This is the process where wind, water or ice may add a layer of sediment to a landform.

MA_775_DIABLO [31]

Answer:

Deposition

Explanation:

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4 years ago

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A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,

Scorpion4ik [409]

<u>Answer:</u> The value of $K_c$ is coming out to be 0.412

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For $Sb_2S_3$ </u>

Given mass of $Sb_2S_3$ = 1.00 kg = 1000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $Sb_2S_3$ = 339.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol$

<u>For hydrogen gas:</u>

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol$

<u>For hydrogen sulfide:</u>

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol$

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

$Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)$

Initial: 2.944 5

At eqllm: 2.944-x 5-3x 2x 3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

$\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712$

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$

The expression of $K_c$ for above equation, we get:

$K_c=\frac{[H_2S]^3}{[H_2]^3}$

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

$K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412$

Hence, the value of $K_c$ is coming out to be 0.412

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3 years ago

How much heat is released for 98g of steam to condense?

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The answer to this question is D

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Fill in the coefficients that will balance the following reaction:

dalvyx [7]

Answer:

C₃H₈₍g₎ + 5O₂₍g₎→ 3CO₂₍g₎ + 4H₂O₍l₎

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Propane is an alkane that burns in enough oxygen to produce carbon (iv) Oxide and heat as the only by products. Balancing the equation: The number of atoms of each kind on either side should be equal. Hydrogen on the left has eight atoms same as the right side after balancing, oxygen has 10 while carbon has 3 on each side.

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