Answer:
Shannon run 1.5 km more on Friday than on Saturday.
Step-by-step explanation:
From the given table
- Distance run on Friday = 4/2 = 2 km
- Distance run on Saturday = 1/2 = 0.5 km
- In order to run how many more kilometers Shannon run on Friday than on Saturday, we need to subtract the distance run on Saturday from the distance run on Friday.
i.e.
Friday run - Saturday run = 2 - 0.5
= 1.5 km
Thus, Shannon run 1.5 km more on Friday than on Saturday.
Answer: The required values are
x = 12 units, ST = 60 units and SU = 120 units.
Step-by-step explanation: Given that T is the midpoint of SU, where
ST = 5x and TU = 3x + 24.
We are to find the values of x, ST and SU.
Since T is the midpoint of SU, so we get
So, the value of x is 12.
Therefore,
and
Thus, the required values are
x = 12 units, ST = 60 units and SU = 120 units.
Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
