Answer:
I believe it might be point A since the question ask what will result in the ln a largest increase in potential energy
Explanation:
Explanation:
An electrical circuit needs:
a source of electrical power (this could be a power plant or a battery)
a material along which the electricity can flow (this may be a copper wire)
something to power (this could be a bulb)
The circuit is connected in a loop. Then, the source of power pushes electrons around the wire. It lights the bulb and continues in the circuit until it is broken.
A simple circuit lights one bulb. More difficult circuits might have several switches and loops. This would allow different groups of lights to be turned on or off at the same time.
( I hope this was helpful) >;D
Read more: All in a Circuit - What Makes a Circuit?, Battery Power, How a Battery Works, Flat!, Home Circuits, Conductors and Insulators - JRank Articles https://science.jrank.org/kids/pages/232/All-in-Circuit.html#ixzz6qWd5gxGf
Answer:
a) 2.53 * 10^-2 m/s
b) -4.78 * 10^-2 m/s
c) 1.21 * 10^-1 m/s
Explanation:
Given data :
Mass of block = 10 kg
Measuring 250mm on each side
a) calculate the speed when a force of 75N is applied to pull block upwards
F = f + W sin∅ ( equation for applying the force of equilibrium condition in the x axis ) ----- ( 1 )
f ( friction force )= ( 16400v * 6.25 *10^-2) = 1025 v
F ( force applied ) = 75
W ( weight of block ) = 10 * 9.81 = 98.1 N
∅ = 30°
input values into equation 1
V = 
= 2.53 * 10^-2 m/s
b) Speed when no force is applied on the block
F = f + W sin∅
F = 0
f = 1025 V
W = 98.1 N
∅ = 30°
hence V = 
= - 4.78 * 10^-2 m/s
c) when a force is applied to push block down the incline
F = f + W sin∅ ----- ( 3 )
F = 75 N
f = 1025 V
W = 98.1 N
∅ = 30°
input values into equation 3 considering the fact that the weight of the block is acting in the opposite direction
75 = 1025 V - 98.1 ( sin 30° )
V = 
= 1.21 * 10^-1 m/s
Well 0 because if you multiply anything by 0 it will conclude to 0 and number 2 is the same answer hope you got it
Answer:
Explanation:
If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.
mgh = ½mv²
v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... = 6.26 m/s
However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy
mgh = ½mv² + ½Iω²
mgh = ½mv² + ½(½mR²)(v/R)²
2gh = v² + ½v²
2gh = 3v²/2
v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = 5.11 m/s
