Answer: Option (c) is the correct answer.
Explanation:
An elastic object is defined as the object that is able to retain its shape when a force is applied on it.
For example, when we pull a rubber band then it stretches and when we withdraw the force applied on it then it retain its shape.
As we know that potential energy is the energy obtained by an object due to its position.
So, when we stretch a rubber band then it will have elastic potential energy as position of the rubber band is changing and since, it will retain it shape hence it has elastic potential energy.
Thus, we can conclude that a stretched rubber band has elastic potential energy.
Answer:
h ’= 0.51356 m
Explanation:
For this exercise we can use conservation of energy
starting point. Highest point of the trajectory
Em₀ = m g h
sin θ = h / L
h = L sin θ
Em₀ = m g L sin θ
final point. Lowest point of the trajectory
Em_f = K = ½ mv²
as there is no friction, energy is conserved
Em₀ = Emf
m g L sin θ = ½ m v²
sin θ = ½ v² / gL
sin θ = ½ 3.80² / (9.8 6.60)
sin θ = 0.111626
tea = 6.41
They ask us for the speed for L ’= 4.60 m
let's find the height
sin 6.41 = h '/ L'
h ’= L’ sin 6.41
h ’= 4.60 sin 6.41
h ’= 0.51356 m
we use conservation of energy
m g h ’= ½ m v’2
v ’= √ (2gh’)
v ’= √ (2 9.8 0.51356)
v ’= 3.173 m /s²
Complete Question
The complete question is shown on the first uploaded image
Answer:
The wavelength is
Explanation:
From the question we are told that
The distance of the slit to the screen is 
The order of the fringe is m = 6
The distance between the slit is
The fringe distance is 
Generally the for a dark fringe the fringe distance is mathematically represented as
![Y = \frac{[2m - 1 ] * \lambda * D }{2d}](https://tex.z-dn.net/?f=Y%20%20%3D%20%5Cfrac%7B%5B2m%20%20-%201%20%5D%20%2A%20%20%5Clambda%20%2A%20%20D%20%20%7D%7B2d%7D)
=> ![\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7BY%20%2A%20%202%20%2A%20%20d%20%7D%7B%5B2%2Am%20%20-%20%201%5D%20%2A%20%20D%7D)
substituting values
=> ![\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7B0.019%20%2A%20%202%20%2A%20%200.9%2A10%5E%7B-3%7D%20%7D%7B%5B2%2A6%20%20-%20%201%5D%20%2A%20%205%7D)
=> 

An example of objects that move in revolution is a ball on a string end or a planet that is moving around a star.
<u>Explanation:</u>
Rotation is the movement of an object in circular path. When the rotation's axis does not pass through the object, it is revolution. The axis of rotation may also be out of the object completely. This results in making the object to revolve around the rotation's axis. An object going in an elliptical path is revolution.It is the total time taken to complete one orbit.
Some of the examples for an object revolving are the following:
- A ball on the string end.
- A planet that revolves around a star. An orbit is a term that is used to describe this type of motion.
<span>In our system an astronomical unit is the average distance from the earth to the sun which is about 93 million miles. (92,957,000 miles) This is known as 1 AU.</span>