Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.
An electron is released from rest at a distance of 0 m from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² . How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?
Answer:
Work=1.06×10⁻²¹J
Explanation:
Given Data
Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²
Charge density σ=3.90×10⁻¹² C/m²
The electron moves a distance d=3.00×10⁻²m
Electron charge e=-1.6×10⁻¹⁹C
To find
Work done
Solution
The electric field due is sheet is given as
E=σ/2ε₀

Now we need to find force on electron

Now for Work done on the electron
Answer:
The answer is
<h2>2560 J</h2>
Explanation:
The kinetic energy of an object given it's mass and velocity can be found by using the formula

where
m is the mass
v is the velocity
From the question
m = 80 kg
v = 8 m/s
The kinetic energy is

We have the final answer as
<h3>2560 J</h3>
Hope this helps you
Answer:
The frequency of radiation is 
Explanation:
Given:
Wavelength
m
Speed of light

For finding the frequency of radiation,




Therefore, the frequency of radiation is 
(A) Standing waves are created by two identical waves reflecting off each other
(B) a general definition of a wave interference is, when more than on wave meet and interact in the same medium
Hope this helps :)