Answer:
Explanation:
Given the following data;
Frequency = 4.0 x 10⁹ Hz
Planck's constant, h = 6.626 x 10-34 J·s.
To find the energy of the electromagnetic wave;
Mathematically, the energy of an electromagnetic wave is given by the formula;
E = hf
Where;
E is the energy possessed by a wave.
h represents Planck's constant.
f is the frequency of a wave.
Substituting the values into the formula, we have;
A) 11.1 cm
We can find the focal length of the lens by using the lens equation:
where
f is the focal length
p = 16.0 cm is the distance of the object from the lens
q = 36.0 cm is the distance of the image from the lens (taken with positive sign since it is on the opposide side to the image, so it is a real image)
Solving the equation for f:
B) Converging
The focal length is:
- Positive for a converging lens
- Negative for a diverging lens
In this case, the focal length is positive, so it is a converging lens.
C) 18.0 mm
The magnification equation states that:
where
is the heigth of the image
is the height of the object
Solving the formula for , we find
So the image is 18 mm high.
D) Inverted
From the magnification equation we have that:
- When the sign of is positive, the image is erect
- When the sign of is negative, the image is inverted
In this case, is negative, so the image is inverted.