Question

What is the area of a trapezoid that has the bases of 1 1/4ft and 14 inches and a height of 3 inches.

Answer 1

The area of the trapezoid is 43.5 inches²

Step-by-step explanation:

The formula of the area of a trapezoid is $A=\frac{1}{2}(b_{1}+b_{2})h$ , where:

• $b_{1}$ and $b_{2}$ are the two parallel bases
• h is its height

∵ $b_{1}$ = $1\frac{1}{4}$ feet

∵ $b_{2}$ = 14 inches

∵ h = 3 inches

- Change the length of $b_{1}$ from feet to inches

∵ 1 foot = 12 inches

∴ $1\frac{1}{4}$ feet = $1\frac{1}{4}$ × 12 = 15 inches

∴ $b_{1}$ = 15 inches

Substitute the values of $b_{1}$ , $b_{2}$ and h in the

formula of the area

∴ $A=\frac{1}{2}(15+14)(3)$

∴ A = 43.5 inches²

The area of the trapezoid is 43.5 inches²

Learn more:

You can learn more about the area of figures in brainly.com/question/12919591

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