Answer:
the questions they could ask would be:
how much will the temperature change?
how much pressure will there be?
how durable does the equipment need to be?
how do we know if we will run into a water pocket or a magma pocket?
Explanation:
Answer:
11.8 Joules
Explanation:
Given:-
- The height of the target ball, si = 0.860 m
- The mass of target and steel ball, m = 0.012 kg
- The target ball travels a distance ( x ) after being struck = 1.40 m
Find:-
What is the kinetic energy (in joules) of the target ball just after it is struck?
Solution:-
- We are given the initial distance of the target ball as 0.86 m above the floor which travels a distance ( x ) after being struck.
- We will employ the one dimensional kinematic equation of motion to determine the initial velocity ( vi ) of the target ball as follows:
Where,
vf: The final velocity of target ball at maximum height = 0
g: The gravitational acceleration constant = 9.8 m/s^2
- Plug in the required parameters and evaluate the ( vi ) as follows:
- The kinetic energy ( Ek ) of an object with mass ( m ) and initial velocity ( vi ) is expressed as:
Answer: The kinetic energy of the target ball just after it is struck is 11.8 Joules.
Answer:
Explanation:
Given the following data;
Original volume = V
New volume = V'
Original temperature = T
New temperature = T'
To write an expression for Charles's law;
Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Charles law is given by the formula;
We study the movement of each body separately. For the mass body A: vector: T + Na + Ga + Ff = ma * a.Scalar: on the axis Ox: ma * g * sinα-T-Ff = ma * a
On the axis Oy: Na-ma * gcosα = 0=>Na=ma * g*cosα
Ff=μ*N=μ*ma * g*cosα
ma * g * sinα-T-μ*ma * g*cosα=ma*a
For mass body B: vector: Gb + T = mb * a.Scalar: by projection of the vector relation on the axis Ox:T-mb*g=mb*a
Answer:
78 miles
Explanation:
The average velocity of the bus is given by:
where
d is the displacement (the distance between the two cities)
t is the time taken
In this problem, we have
t = 1.5 h
v = 52 mph
So, we can solve the formula to find d, the distance between the cities: