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iris [78.8K]
4 years ago
7

If an experiment used 945 j of heat, how many calories (cal) is that?

Physics
1 answer:
irina1246 [14]4 years ago
5 0
There are approximately two hundred and twenty-five point seven five calories from using 945 j of heat

A: 225.75
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<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

a_{c} =\frac{v^{2} }{r}

Where a_{c} is the centripetal acceleration

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From the given information

v = 12 \ m/s

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a_{c} =\frac{12^{2} }{30}

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2 years ago
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