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Archy [21]
2 years ago
12

You need a clear and steady blood

Physics
2 answers:
Crank2 years ago
8 0

Answer:

B. oxygen

Explanation:

Alika [10]2 years ago
5 0

Answer:

it's oxygen lolllllllllllll they kinda need it

Explanation:

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In your own words describe how matter is defined
gizmo_the_mogwai [7]

Matter is any substance that has mass and takes up space.

5 0
3 years ago
Aunt Matilda goes to a well and throws a penny straight down the well at 3.0 m/s. She hears a splash after 0.5 seconds. How deep
nevsk [136]

Answer : The correct option is (d) 2.73 m

Explanation :

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2

where,

s = distance or height = ?

u = initial velocity  = 3.0 m/s

t = time = 0.5 s

a = acceleration due to gravity = 9.8m/s^2

Now put all the given values in the above equation, we get:

s=(3.0m/s)\times (0.5s)+\frac{1}{2}\times (9.8m/s^2)\times (0.5s)^2

s=2.73m

Therefore, the correct option is (d) 2.73 m

8 0
3 years ago
PLS I NEED HELP ASAAP​
Lerok [7]

Answer:

Option A

Explanation:

The Equation represents the displacement of the object which is represented by x

x=t-t^2

so, x_0  means when time is zero so we replace t with zero in the equation,

x_0=(0)-(0)^2\\x_0=0

now for v which is velocity we need to differentiate the function as the formula for velocity is rate of change of displacement over time so we derivate the equation once and get,

v=1-2t\\

now for  v_0  we insert t = 0 and get

v_0=1-2(0)\\v_0=1

now for a which is acceleration the formula of acceleration is rate of change of velocity over time, so we differentiate the the equation of v(velocity) once or the equation of x(displacement) twice so now we get,

a=-2

so Option A is your answer.

Remember derivative of a constant is always zero because a constant value has no rate of change has its a constant hence the derivative is 0

5 0
2 years ago
Does decomposing water require high activation energy
skelet666 [1.2K]
decomposing water does not require High activation energy
6 0
3 years ago
Susan is quite nearsighted; without her glasses, her far point is 34 cm and her near point is 17 cm . Her glasses allow her to v
butalik [34]

Answer:

u=34cm

Explanation:

From the question we are told that:

Far point is V=34 cm

Near point is u=17 cm

Therefore

Focal Length

f=-34cm

Generally the equation for the Lens is mathematically given by

\frac{1}{u}=\frac{1}{f}-\frac{1}{v}

\frac{1}{u}=\frac{1}{-34}-\frac{1}{-17}

u=34cm

5 0
2 years ago
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