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3 years ago

Why does soda fizz when you poor it into a cup?

2 answers:

6 0

Because all of the carbonation in the can. The pressure builds and when it is released it forms a fizz.

Happy studying ^-^

mestny [16]3 years ago

5 0

Bc of its carbonation

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A catalyst is used in the chemical reaction to break down hydrogen peroxide into water and oxygen. At the end of the reaction, t

Natasha_Volkova [10]

At the end of the reaction, the catalyst is UNCHANGED.
:)

8 0

4 years ago

Question #1: Identify the type of Mutation below

borishaifa [10]

Answer:

Deletion

Explanation:

A mutation refers to a change in the DNA sequence. This means that the original sequence of bases in the DNA has been altered permanently.

There are three types of DNA mutations; base substitutions, deletions and insertions.

In the particular case of this question, the original is TTCGATA while the copy is TTGATA. If you look closely at the two, you will notice that the C has been omitted. This is an example of deletion.

5 0

3 years ago

Draw the product of the reaction CH3CH2CH2CH2C?CCH3+2Br2??

svetlana [45]

I will assume that the sign ? between the C and the CCH3 is a triple bond, and I will represent it by three vertical lines |||

So the reaction is:

CH3CH2CH2CH2C ||| CCH3+2Br2 ---->

This is a typical reaction known as halogenation of alkines.

This is an addition reaction, i.e. the alkyne undergoes an addition of the Br2 (and it also happens with Cl2) to the triple bond to form a tetra halide.

.
 Br Br
 | |
CH3CH2CH2CH2C ||| CCH3+2Br2 ----> CH3 CH2 CH2 CH2 C - C - CH3
 | |
 Br Br

3 0

3 years ago

What is your dream job or ideal lifestyle?

blondinia [14]

My dream job is to create my own business and become my own boss

7 0

3 years ago

A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10

lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

6 0

4 years ago