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Shtirlitz [24]
3 years ago
9

consider a triangle ABC like the one below suppose that a=23 b=14 c=27 (the figure is not drawn to scale.) solve the triangle. c

arry your intermediate computations at least four decimal places, and round your answers to the nearest tenth. If there is more than one solution use the button labeled "or"​

Mathematics
1 answer:
marusya05 [52]3 years ago
8 0

Answer:

find abc

Step-by-step explanation:

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Simplify this expression.
Grace [21]
11x2 would be your answer.
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3 years ago
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Let f(x) = 5x2 – 4x and g(x) = 5x + 1.
Nastasia [14]

f(x) = 5x^2 - 4x

g(x) = 5x + 1

Therefore f - g = 5x^2 - 4x - (5x + 1)

= 5x^2 - 4x - 5x -1

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8 0
3 years ago
Read 2 more answers
What is 20% of 180<br>please i realy need to answer this​
blagie [28]

Answer:

36

20 percent * 180 =

(20:100)* 180 =

(20* 180):100 =

3600:100 = 36

Now we have: 20 percent of 180 = 36

Question: What is 20 percent of 180?

Percentage solution with steps:

Step 1: Our output value is 180.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$180=100\%$.

Step 4: Similarly, $x=20\%$.

Step 5: This results in a pair of simple equations:

$180=100\%(1)$.

$x=20\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{180}{x}=\frac{100\%}{20\%}$

Step 7: Again, the reciprocal of both sides gives

Step-by-step explanation:

Hope it is helpful.....

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How do I do algebra?
Zielflug [23.3K]
You multiply and add like terms, depending on the equation that you have
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Given the tables for f &amp; g below, find the following: x f ( x ) g ( x ) 0 9 7 1 4 8 2 3 6 3 5 1 4 7 5 5 1 2 6 6 0 7 0 4 8 2
d1i1m1o1n [39]

\\(i)\\&#10;\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\\&#10;\\&#10;f_{avg}=\frac{f(b)-f(a)}{b-a}\\&#10;\\&#10;\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\\&#10;\\&#10;g_{avg}=\frac{g(7)-g(3)}{7-3}\\&#10;\\&#10;=\frac{4-1}{4}\\&#10;\\&#10;=\frac{3}{4}\\&#10;\\&#10;\text{so average rate of change of g on interval [3,7] is }\frac{3}{4}

\\(ii)\\  \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\\&#10;\\&#10;f_{avg}=\frac{f(7)-f(3)}{7-3}\\&#10;\\&#10;=\frac{0-5}{4}\\&#10;\\&#10;=\frac{-5}{4}\\&#10;\\&#10;\text{so average rate of change of g on interval [3,7] is }\frac{-5}{4}

\\(iii)\\&#10;\text{Since g(4)=5, so we have}\\&#10;\\&#10;f(g(4))=f(5)\\&#10;\\&#10;\text{since the value of f is 1 at x=5. so }\\&#10;\\&#10;f(g(4))=f(5)=1\\&#10;\\&#10;\text{hence we have, }f(g(4))= 1

\\(iv)\\&#10;\text{Since f(3)=5, so we have}\\&#10;\\&#10;g(f(3))=g(5)\\&#10;\\&#10;\text{since the value of g is 2 at x=5. so }\\&#10;\\&#10;g(f(3))=g(5)=2\\&#10;\\&#10;\text{hence we have, }g(f(3))= 2

5 0
3 years ago
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