Answer:
Los usos de la plata son cientos, sobre todo en procesos industriales, comerciales y hasta personales. Su resistencia a la corrosión la hace ideal para la elaboración de recipientes especiales o para recubrir otros metales.
Explanation:
Answer: you can use a table to group them together.
Explanation: use a table, graph or organizer
I searched for complete question (as your question is missing with structure) and found the structure of compound attached below.
Answer: The compound can
neither act as a Hydrogen Bond Donor
nor act as a Hydrogen Bond Acceptor.
Explanation: For two compounds to build Hydrogen Bond Interactions it is compulsory that they must contain Hydrogen atoms which are directly attached to most electronegative atoms like
Fluorine,
Oxygen and
Nitrogen.
As the given compound is
2-Butene (a non polar hydrocarbon), it lacks partial positive Hydrogen (which can act as Hydrogen Bond Donor) and a most electronegative element (F, O or N) which can act as Hydrogen Bond Acceptor. Therefore, this compound will not generate any Hydrogen Bonding with water molecules and will remain immiscible in it.
Answer:
New temperature T2 = -124.7 °C
Explanation:
Given:
Old volume V1 = 135 cm³
New volume V2 = 140 cm³3
Old temperature T1 = 143 K
Find:
New temperature T2
Computation:
V1 / T1 = V2 / T2
135 / 143 = 140 / T2
New temperature T2 = 148.3 K
New temperature T2 = 148.3 - 273
New temperature T2 = -124.7 °C