An ion has 12 protons, 14 neutrons, and 10 electrons. the symbol for the ion is
2 answers:
<u>Answer:</u> The ion formed is
<u>Explanation:</u>
An ion is formed when an atom looses or gains electron.
- When an atom looses electrons, it will form a positive ion known as cation.
- When an atom gains electrons, it will form a negative ion known as anion.
Atomic number is defined as the number of protons or electrons that are present in a neutral atom.
Atomic number = number of protons = number of electrons
Atomic mass is defined as the sum of number of protons and neutrons that are present in an atom.
Atomic mass = Number of protons + Number of neutrons
The isotopic representation of an atom is:
where,
Z = Atomic number of the atom
A = Mass number of the atom
X = Symbol of the atom
We are given:
Number of protons = 12
Number of neutrons = 14
Atomic Mass = 12 + 14 = 26
Number of electrons = 10
As, the number of electrons is less than the number of protons, it forms positive ion
Hence, the ion formed is
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3.08 is the pOH of a 0.175 M aqueous solution of .
0.215% is the per cent ionization of a 0.325 M aqueous solution of
pH is a measure of how acidic/basic water is.
A)
→
Kb = 4.5 x
Kb = {concentration of (NH₄⁺) x concentration of (OH⁻)} ÷ concentration of (NH₃).
concentration of (NH₄⁺) = concentration of (OH⁻) = x.
x² = Kb x concentration of (NH₃)
x² = 4.5 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.
x = concentration of (OH⁻) = √(7.0 × 10⁻⁷)
= 8.367 × 10⁻⁴
pOH = -log(c(OH⁻))
=- log ( 8.367 × 10⁻⁴)
= 3.08
B)
Chemical reaction: NX₃ + H₂O ⇄ NX₃H⁺ + OH⁻.
Concentration of (NX₃) = 0.325 M.
Kb = 4.5 x 10⁻⁶.
[NX₃H⁺] = [OH⁻] = x.
[NX₃] = 0.325 M - x.
Kb = [NX₃H⁺] x [OH⁻] ÷ [NX₃].
4.5 x 10⁻⁶ = x² ÷ (0.325 M - x).
x = 0.0007 M.
Per cent of ionization:
α = 0. 0007 M ÷ 0. 325 M x 100%
= 0.215%.
Hence,
3.08 is the pOH of a 0.175 M aqueous solution of .
0.215% is the per cent ionization of a 0.325 M aqueous solution of
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