All categories

3 years ago

Please help ASAP I also need the answer for part b also

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

8 0

Depending on how large the figure actually is, if it is specifying that on that specific paper what to use to measure it, use a ruler also for part b a possible dimension could be 4 cm x 8cm

You might be interested in

Question 7 of 10

Lapatulllka [165]

I believe it's graph C! I hope it will help you...

5 0

2 years ago

Read 2 more answers

Simplify 16 - 12 ÷ 4 +3 (6-2) show working plz

ira [324]

Answer:

Step-by-step explanation:

16-12/4+3(6-2) subtract 6 and 2

16-12/4+3+4 divide 12 and 4

16-3+3+4 subtract 16 and 3

13+3+4 add all 3 numbers

13+7

4 0

3 years ago

Divide 40x 64y by 5x 8y

velikii [3]

If you would like to solve (40 * x * 64 * y) / (5 * x * 8 * y), you can calculate this using the following steps:

(40 * x * 64 * y) / (5 * x * 8 * y<span>) = 8 * 8 = 64
</span>
The correct result would be 64.

6 0

3 years ago

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

brilliants [131]

Answer:

(a) 11.25 and 1.68

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 15

r = number of success

p = probability of success which in our question is % of cases in

which customer problems are resolved on the same day, i.e.;75%

So, here X ~ $Binom(n=15,p=0.75)$

(a) Expected number of problems to be resolved today = E(X)

E(X) = $\mu$ = n * p = 15 * 0.75 = 11.25

Standard deviation = $\sigma$ = $\sqrt{n*p*(1-p)}$ = $\sqrt{15*0.75*(1-0.75)}$ = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

P(X = 10) = $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}$

= $3003*0.75^{10} *0.25^{5}$ = 0.1651

= $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}$

= $3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4}$ = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}$

= $1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}$

= 0.6865

3 0

3 years ago

What is the answer !

kondor19780726 [428]

Answer:

m∠OKG = 95°

Step-by-step explanation:

In the given question,

Angle OKL and angle OKG are the linear pairs.

And we know that sum of linear pair of angles is 180°.

Therefore, m∠OKL + m∠OKH = 180°

85° + m∠OKH = 180°

m∠OKH = 180° - 85°

= 95°

Therefore, measure of angle OKG = 95° will be the answer.

3 0

3 years ago