Answer: 2. Determine the molarity of 2.5 L solution made with 698g rubidium chloride (RbBr).
Explanation:
The answer would be Rocks, metals, hydrogen compounds, hydrogen and helium, all in gaseous form.
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Answer:
f = 0.94 ×10²⁴ Hz
Explanation:
Given data:
Frequency of light = ?
Wavelength of light = 3.2 ×10⁻¹⁶ m
Solution:
Formula:
Speed of light = wavelength × frequency
c = λ × f
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = f × 3.2 ×10⁻¹⁶ m
f = 3×10⁸ m/s / 3.2 ×10⁻¹⁶ m
f = 0.94 ×10²⁴ s⁻¹
f = 0.94 ×10²⁴ Hz (Hz = s⁻¹)
Answer:
0.382 g
Explanation:
Let's consider the reduction of gallium (III) to gallium that occurs in the electrolysis.
Ga³⁺ + 3 e⁻ → Ga
We can establish the following relations:
- 1 minute = 60 second
- 1 Ampere = 1 Coulomb / second
- The charge of 1 mole of electrons is 96,468 Coulomb (Faraday's constant)
- 1 mole of gallium is deposited when 3 moles of electrons circulate.
- The molar mass of gallium is 69.72 g/mol
We will use this that to determine the mass of gallium deposited from a Ga(III) solution using a current of 0.880 A that flows for 30.0 min