Answer: seen below.
Explanation: since the different means use in treating rabbit muscle mitochondria containing PDH complex. I will give different reactions that occurs.
The mitochondria preparation responds as follow;
Active pyruvate dehydrogenase (dephosphorylated) is converted to inactive pyruvate dehydrogenase (phosphorylated) and the rate of conversion of pyruvate to acetyl-CoA decreases.
The phosphoryl group on pyruvate dehydrogenase (dephosphorylated) phosphate is removed enzymatically to give active pyruvate dephosphorylated which increases the rate of conversion of pyruvate to acetyl-CoA.
Malonate inhibit succinate dehydrogenase, and citrate accumulates. Accumulation of this citrate inhibits citrate synthase, and acetyl-CoA accumulates. Increased level of this acetyl-CoA inhibits pyruvate dephosphorylated and the rate of conversion of pyruvate to acetyl-CoA decreases.
Answer:
- 4.5+2.34= 6.84
- 4.5-5 =-0.5
- 6.00+3.411= 9.411
- 3.4×2.32 = 7.888
- 7.77/2.3= 3.37
7. 1200×23.4=28080
9. = 78.512
10. =341.199
11= 7.45
12 =65.0023
13.=3400210.34
Explanation:
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From he calculations, we can see that the total pressure at equilibrium is 21 atm.
<h3>What is equilibrium constant?</h3>
The term equilibrium constant commonly describes the constant that that shows the extent of conversion of reactants to products.
We have to find the pressure of each gas as follows;
For H2
P = nRT/V = 4.553 /2 × 0.082 × 1000/8.89 L = 21 atm
Using the ICE table;
C(s) + 2H2(g) ⇌ CH4(g)
I 21 atm 0
C -x +x
E 21 - x x
0.263= x/(21 - x )^2
0.263(21 - x )^2 = x
38 - 11x - 0.263x^2 = x
0.263x^2 + 12x - 38 = 0
x=2.97 atm
At equilibrium, we have;
(21 - 2.97) + 2.97 = 21 atm
Learn more about equilibrium constant: brainly.com/question/17960050
The volume of a 5cm cube is 0.5dm*0.5dm*0.5dm = 0.125dm^3
1dm^3 = 1l
So 0.125dm^3 = 125mL
This gives us 2410/125 = 19.28
So the density of gold is 19.28g/mL
Final check: Gold is indeed 19.3g/mL
Here’s a simplified explanation.
The <em>protons</em> in the nucleus <em>repel each other</em>. The <em>neutrons provide the “glue”</em> that holds the nucleus together and prevents it from flying apart.
The “glue” is the strong nuclear force. It is strong but extremely short range. It falls off extremely rapidly as the p-n distance increases.
A <em>neon atom</em> has 10 protons. There are three stable isotopes, with 10, 11, and 12 neutrons.
With fewer than 10 protons, the glue is not strong enough to hold the nucleus together.
If there are more than 12 neutrons, the average p-n distance is great enough that the glue has again become too weak.
<em>Gold</em> has one stable isotope. It contains 79 protons and 118 neutrons.
If there are fewer than 118 neutrons, the proton repulsions will be too strong for the strong force. If there are more than 118 neutrons, the average p-n distance will be large enough that the glue will again be too weak to hold the nucleus toge
ther.
