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3 years ago

A greater applied force is required to move an object with a greater mass than one with a smaller mass.

Physics

2 answers:

4vir4ik [10]3 years ago

7 0

Answer:

True

Explanation:

The bigger an object is, the more force you must apply to move the object. Think about it like moving a mouse compared to moving an elephant. You can't move the elephant by yourself, because you don't have enough strength or force to move it. But, you can easily pick up a mouse, because it requires less force, or strength. Hope this helped :)

ipn [44]3 years ago

6 0

Answer:

I don't know

Explanation:

sorry but I will help u next time kk

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A 0.119 kg ball is dropped from rest. if the magnitude of the ball's momentum is 0.817 kg·m/s just before it lands on the ground

NemiM [27]

I am not good at math but what grade r u in cause i am in 9th and if u r then i might can help

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3 years ago

A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest orde

True [87]

Answer:

The order of maximum is $n = 5$

Explanation:

From the question we are told that

The diffraction grating is k = 300 lines per mm = 300000 lines per m

The wavelength is $\lambda = 630 \ nm = 630 *10^{-9} \ m$

Generally the condition for constructive interference is mathematically represented as

$dsin \theta = n * \lambda$

Here n is the order maximum

d is the distance the grating which is mathematically represented as

$d = \frac{1}{k}$

=> $d = \frac{1}{300000}$

=> $d = 3.3*10^{-6}\ m$

$n = \frac{dsin \theta}{ \lambda}$

at maximum $sin\theta = 1$

$n = \frac{d}{\lambda}$

=> $n = \frac{3.3*10^{-6}}{630 *10^{-9}}$

=> $n = 5$

8 0

3 years ago

A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.

Gekata [30.6K]

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] = $6.5*10^{4}\ m/s$

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity $[\theta]$ = 15 degree.

We are asked to calculate the magnetic force experienced by the charged particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force $\vec F=q(\ \vec V \times \vec B)$

i.e F = $=qVBsin\theta$

$=6.8*6.5*10^{4}*1.4*sin15$

$=61.88*10^{4}sin15$

$=61.88*10^4*0.2588\ N$

$=16.016*10^4\ N$

$=1.6*10^5\ N$

Hence, the force experienced by the charged particle is C i.e $1.6*10^5 N$

4 0

3 years ago

Read 2 more answers

Which of the following types of electromagnetic radiation has the highest energy?

Varvara68 [4.7K]

B. Gamma rays
Gamma rays have highest energy

3 0

3 years ago

a cliff diver drops from rest to the water below. how many seconds does it take for the diver to go from 0 to 60. that is to go

aleksandr82 [10.1K]

U = 0, initial vertical velocity
v = 60 mph = 88 ft/s

Ignore air resistance and take g = 32 ft/s².
It t = time to attain 60 mph, then
(88 ft/s) = (32 ft/s²)*(t s)
t = 88/32 = 2.75 s

Answer: 2.75 s

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3 years ago